How many moles of sodium iodide are needed to remove 5.95×10−6 mol of o3?

1 answer:

8 0

You have to find the reaction involving sodium iodide and ozone or O₃. If you search in the internet, the reaction would be

O₃(g) + 2 NaI(aq) + H₂O(l) → O₂(g) + I₂(g) + 2 NaOH(aq)

Using the stoichiometric coefficients in the reaction, the solution would be

5.95×10⁻⁶ mol O₃ * (2 mol NaI/1 mol O₃) = 1.19×10⁻⁵ mol NaI

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<h3>Further explanation</h3>

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vaieri [72.5K]

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