Here is the answer of the given question
Answer:
Al(OH)₃(aq) + 3 HBr(aq) ⇒ AlBr₃(aq) + 3 H₂O(l)
Explanation:
Let's consider the unbalanced equation for the reaction between solid aluminum hydroxide and a solution of hydrobromic acid. This is a neutralization reaction so it forms a salt, aluminum bromide, and water.
Al(OH)₃(aq) + HBr(aq) ⇒ AlBr₃(aq) + H₂O(l)
We start balancing Br atoms by multiplying HBr by 3.
Al(OH)₃(aq) + 3 HBr(aq) ⇒ AlBr₃(aq) + H₂O(l)
To get the balanced equation, we must multiply H₂O by 3 as well.
Al(OH)₃(aq) + 3 HBr(aq) ⇒ AlBr₃(aq) + 3 H₂O(l)
Answer:
Azucar, bicarbonato de sodio, lavandina, vinagre, amoniaco.
Explanation:
Podemos numerar estos compuestos
Azucar → Sacarosa → C₁₂H₂₂O₁₁
Lavandina → Hipoclorito de sodio → NaClO
Vinagre → Ácido acético → CH₃COOH
Bicarbonato de sodio → NaHCO₃
Amoníaco → NH₃
Nitrogen trifluoride is the inorganic compound with the formula NF3. This nitrogen-fluorine compound is a colorless, odorless, nonflammable gas. It finds increasing use as an etchant in microelectronics.
(If you mean by a gas of some sort)