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weeeeeb [17]
3 years ago
14

This for number 8 and 9

Chemistry
1 answer:
3241004551 [841]3 years ago
6 0

Okay for 8 it is the maximum levels will be higher and for 9 is poor circulation leads to lack of nutrients and oxygen

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What is the act of adding fluid such as distilled water to a powdered or crystaline form?
nata0808 [166]

Reconstitution is the act of adding fluid such as distilled water to a powdered or crystalline form.

Additionally, medications are frequently provided in dry form, such as powders or crystals, which must be reconstituted with liquid before being injected parenterally. To create a specified liquid concentration, a dry ingredient is reconstituted by adding a liquid diluent. To ensure that the drug is reconstituted in the exact concentration, it is crucial to carefully follow the reconstitution instructions. The quantity of fluid used to dilute the drug must also be taken into account when determining the dosage of reconstituted medication to provide to the patient.

Learn more about Reconstitution here-

brainly.com/question/791594

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6 0
2 years ago
When naming a transition metal ion that can have more than one common ionic charage, the numerical value of the chrage is indica
alexandr1967 [171]
The answer is a Roman numeral.
Ex:
1: I
2: II
3: III
4: IV
5: V
6: VI
7: VII
8: VIII
9: IX
10: X
6 0
3 years ago
An aqueous solution containing 100.0 g of nacl and 100.0 g of cacl2 has a volume of 1.00 l and a density of 1.15 g/ml. the vapor
Lemur [1.5K]
Missing question: What is the vapor pressure of the solution at 25°<span>C?
n(NaCl) = 100 g </span>÷ 58,4 g/mol.
n(NaCl) = 1,71 mol. 
NaCl → Na⁺ + Cl⁻, amount of ions are 2 · 1,71 mol = 3,42 mol.
n(CaCl₂) = 100 g ÷ 111 g/mol = 0,9 mol.
CaCl₂ → Ca²⁺ + 2Cl⁻, amount of ions 3 · 0,9 mol = 2,7 mol.
m(solution) = 1000 ml (1,00 L) · 1,15 g/ml = 1150 g.
m(H₂O) = 1150 g - 100 g - 100 g = 950 g.
n(H₂O) = 950 g ÷ 18 g/mol = 118,75 mol.
<span>water's mole fraction = 118,75 mol </span>÷ (118,75 mol + 2,7 mol + 3,42 mol).
water's mole fraction = 0,95.
p(solution) = 0,95 · 23 mmHg = 21,85 mmHg.

6 0
3 years ago
A.) A student titrated a 15.00-mL sample of a solution containing a weak, monoprotic acid with NaOH. If the titration required 1
nikklg [1K]

Answer:

A) 0.1225 M

B) 100.4 g/mol

Explanation:

Step 1: Write the generic neutralization reaction

HA(aq) + NaOH(aq) ⇒ NaA(aq) + H₂O(l)

Step 2: Calculate the reacting moles of NaOH

17.73 mL of 0.1036 M NaOH react. The reacting moles are:

0.01773 L × 0.1036 mol/L = 1.837 × 10⁻³ mol

Step 3: Calculate the reacting moles of HA

The molar ratio of HA to NaOH is 1:1. The reacting moles of HA are 1/1 × 1.837 × 10⁻³ mol = 1.837 × 10⁻³ mol.

Step 4: Calculate the molar concentration of HA

1.837 × 10⁻³ moles of HA are in a 15.00 mL volume. The molar concentration is:

M = 1.837 × 10⁻³ mol / 0.01500 L = 0.1225 M

Step 5: Calculate the molar mass of HA

1.837 × 10⁻³ moles of HA weigh 0.1845 g. The molar mass of HA is:

0.1845 g / 1.837 × 10⁻³ mol = 100.4 g/mol

5 0
3 years ago
Who wants to be friends?
nika2105 [10]

Answer:

Meeee

Explanation:

Dis is my new account.

8 0
3 years ago
Read 2 more answers
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