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3 years ago

This for number 8 and 9

Chemistry

1 answer:

3241004551 [841]3 years ago

6 0

Okay for 8 it is the maximum levels will be higher and for 9 is poor circulation leads to lack of nutrients and oxygen

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Match the following terms with their definitions:

stepan [7]

Hi,

Homogeneous mixture 2
Heterogeneous 3
Mixture 1
Solution 5
Compound 4

6 0

3 years ago

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Which of the following would be a clue that a rock is sedimentary?

Masteriza [31]

I do not see any possible answers that you have posted. But a good idea would be that it might have fossils, water currents, mud cracks, usually form in shallow seas. Hope this helps!

8 0

3 years ago

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13. How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe(s) + I'(aq) 12(s) + Fe3+(aq)

Nat2105 [25]

Answer : The correct option is, (C) 6

Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

$Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)$

Half reactions of oxidation and reduction are :

Oxidation : $Fe(s)\rightarrow Fe^{3+}+3e^-$ ......(1)

Reduction : $2I^-(aq)+2e^-\rightarrow I_2$ .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : $2Fe(s)\rightarrow 2Fe^{3+}+6e^-$ ......(1)

Reduction : $6I^-(aq)+6e^-\rightarrow 3I_2$ .......(2)

The overall balanced chemical reaction will be:

$2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)$

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

5 0

3 years ago

Which elements are considered metals? Non-metals? Metalloids?

kolbaska11 [484]

The answer is in the photo.

3 0

3 years ago

A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine

QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we calculate how many NaOH moles reacted, using the definition of molarity:

Molarity = moles / volume

moles = Molarity * volume

0.4293 M * 39.27 mL = 16.86 mmol NaOH

One NaOH moles reacts with one acetic acid mole, so the vinegar sample contains 16.86 mmoles of acetic acid as well.

Finally we calculate the concentration (molarity) of acetic acid:

16.86 mmol HC₂H₃O₂ / 25.00 mL = 0.6743 M

4 0

3 years ago