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BlackZzzverrR [31]
3 years ago
13

What is the solubility of silver chromate in parts per million?

Chemistry
1 answer:
pantera1 [17]3 years ago
4 0
What is the solubility of barium chromate in parts per million?
*parts per million = Grams of Solute/grams of solution X 10^6 (which is ppm)
2.787 x 10^-3g/L x 1L/1000g x 10^6 = 0.02779, or 2.78 x 10^-2ppm

Answer in parts per million to three significant figures =2.78ppm

this is correct for the pearson mastering chemistry question
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Calculate the mass in grams of each sample.
OlgaM077 [116]

Answer: The answer is A. - 4.88x10^20 H2O2 molecules

Explanation: I hope this helps!

4 0
2 years ago
A metal (M) forms an oxide with the formula MO. If the oxide contains 7.17 % O by mass, what is the identity of the metal?
Nataly_w [17]

The metal is lead, Pb.

One unit of the oxide contains one atom of O (16.00 u).

∴ Mass of oxide = 16.00 u O × (100 u MO/7.17 u O) = 223.15 u MO

Mass of M = mass of MO – mass of O = 223.15 u -16.00 u = 207.2 u

The only element with an atomic mass of 207.2 u is lead (Pb) and the formula of the oxide is PbO.

7 0
3 years ago
How many grams of hydrogen are contained in 2.00 mol of C6H7N
Setler [38]

Answer:- 14.0 moles of hydrogen present in 2.00 moles of [tex]C_6H_7N .

Solution:- We have been given with 2.00 moles of C_6H_7N and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:

2.00molC_6H_7N(\frac{7molH}{1molC_6H_7N})(\frac{1.0gH}{1molH})

= 14.0 g H

So, there are 14.0 g of hydrogen in 2.00 moles of  C_6H_7N .

3 0
3 years ago
What is the compound name for the ion chemical formula AgBr?
Gnom [1K]

Answer:

Silver bromide.

Explanation:

4 0
3 years ago
Calculate the weight of 5 atoms of Mg.​
kumpel [21]

Answer:

2.0179701e-22

Explanation:

8 0
3 years ago
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