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Mekhanik [1.2K]
2 years ago
7

What does buffer do?? (Chemistry)​

Chemistry
2 answers:
Lapatulllka [165]2 years ago
8 0

Answer:

C, It resists a change in pH when H+ or OH is added to a solution.

Explanation:

a p e x

pogonyaev2 years ago
4 0
A buffer is a solution that can resist pH change upon the addition of an acidic or basic components. It is able to neutralize small amounts of added acid or base, thus maintaining the pH of the solution relatively stable. This is important for processes and/or reactions which require specific and stable pH ranges. Buffer solutions have a working pH range and capacity which dictate how much acid/base can be neutralized before pH changes, and the amount by which it will change.
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Classify the following statements as observation, inference, prediction, measuring or classifying
Nadusha1986 [10]

Answer:

ggghy I am a great and the other hand the wildcats their own is the name of the

8 0
3 years ago
Determine the mass of water in kg, if 4300 cal of energy is placed in water, resulting in a temperature change to 101.0 oC from
Airida [17]

Answer:

0.5059kg

Explanation:

The heat absorbed for the water is determined using the equation:7

Q = C×m×ΔT

<em>Where Q is heat absorbed (4300cal)</em>

<em>C is specific heat (1cal/g°C)</em>

<em>m is the mass in grams</em>

<em>ΔT is change in °C (101.0°C - 92.5°C = 8.5°C)</em>

<em />

Replacing:

4300cal = 1cal/g°C×m×8.5°C

505.9g = m

In kg, the mass of water is:

<h3>0.5059kg</h3>

<em />

6 0
3 years ago
On a cold morning, the smoke coming out of a chimney is observed to be in blue color. What could be the reason? Name the effect
nirvana33 [79]

Stack effect? I'm not totally sure about this...

Explanation:

Large amount of tiny particles of water droplets, dust and smoke are present on a misty day. These tiny particles in the air scatter blue colour of white light passing through it. When this scattered light reaches our eyes, the smoke appears blue.

6 0
3 years ago
May you please help if you don’t know scroll it you’re 100% thank you
grandymaker [24]

Answer: rise earlier and set later

Explanation: just trust me hope this helps

5 0
3 years ago
Consider the reaction: 2 H2O (g)--&gt;2 H2 (g) + O2 (g). ΔH=483.6 Kj/mol. If 2 moles of H2O (g) are converted H2(g) and O2(g) ag
denis-greek [22]
DE = dH - PdV 

<span>2 H2O(g) → 2 H2(g) + O2(g) </span>

<span>You can see that there are 2 moles of gas in the reactants and 3 moles of gas in the products. </span>

<span>1 moles of ideal gas occupies the same volume as 1 mole of any other ideal gas under the same conditions of temp and pressure. </span>

<span>Since it is done under constant temp and pressure that means the volume change will be equal to the volume of 1 mole of gas </span>

<span>2 moles reacts to form 3 moles </span>

<span>The gas equation is </span>

<span>PV = nRT </span>
<span>P = pressure </span>
<span>V = volume (unknown) </span>
<span>n = moles (1) </span>
<span>R = gas constant = 8.314 J K^-1 mol^-1 </span>
<span>- the gas constant is different for different units of temp and pressure (see wikki link) in this case temp and pressure are constant, and we want to put the result in an equation that has Joules in it, so we select 8.314 JK^-1mol^-1) </span>
<span>T = temp in Kelvin (kelvin = deg C + 273.15 </span>
<span>So T = 403.15 K </span>

<span>Now, you can see that PV is on one side of the equation, and we are looking to put PdV in our dE equation. So we can say </span>

<span>dE = dH -dnRT (because PV = nRT) </span>

<span>Also, since the gas constant is in the unit of Joules, we need to convert dH to Joules </span>

<span>dH = 483.6 kJ/mol = 483600 Joules/mol </span>

<span>dE = 483600 J/mol - (1.0 mol x 8.314 J mol^-1K-1 x 403.15 K) </span>
<span>dE = 483600 J/mol - 3351.77 J </span>
<span>dE = 480248.23 J/mol </span>
<span>dE = 480.2 kJ/mol </span>
5 0
3 years ago
Read 2 more answers
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