Answer:
160
Explanation:
p*v/t = constant
or
p1*v1/t1 = p2*v2/t2
pressure is not stated in question so we get rid of it on both sides
v1/t1 = v2/t2
we are finding temperature so we flip the entire equation
t1/v1 = t2/v2
200/5 = t2/4
4(200/5) = t2
=160
It should be D, cells are parts, tissue is part and organ is part of a system.
The solubility of carbon dioxide at 400 kPa at room temperature is ;
( B ) 0.61 CO2/L
<u>Given data </u>
pressure of CO₂ = 400 Kpa = 3.95 atm
Kh of CO₂ = 3.3 * 10⁻² mol/L.atm
<h3>Calculate the solubility of carbon dioxide </h3>
Solubility = pressure * Kh value of CO₂
= 3.95 atm * 3.3 * 10⁻² mol / L.atm
= 0.13 mol/l CO₂
= 0.61 CO₂ / L
Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l CO₂.
Learn more about solubility : brainly.com/question/23946616
From the options the closest answer is ( B ) 0.61 CO₂ / L
