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Setler79 [48]
2 years ago
9

When .080 moles of propane burn at STP, what volume of carbon dioxide is produced?

Chemistry
1 answer:
rodikova [14]2 years ago
8 0

The volume of carbon dioxide produced is : 5.4 L

<u>Given data:</u>

moles of propane = 0.080 moles

<h3>Determine the volume of Carbon dioxide produced </h3>

The chemical reaction

C₃H₈  + 5O₂  ---- > 3CO₂ + 4H₂O

From the reaction

I mole of C₃H₈ = 3CO₂

0.080 moles of C₃H₈ =  3 * 0.080 = 0.24

Applying the equation below to determine the volume of CO₂

Pv = nRT

    = 0.24 * R * T

v = ( 0.24 * 8.314 * 273 ) / 1 atm

  = 544.7 ml = 5.4 L

Hence we can conclude that The volume of carbon dioxide produced is : 5.4 L

Learn more about Propane burning at STP : brainly.com/question/11903456

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Explanation:

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How is a chemical change different from a physical change?
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6 0
4 years ago
59.23
kramer

Answer:

the proton and the neutron

Explanation:

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Here we see that mass of proton and neutron is approximately similar.

_____________________________________________

Lets see what is  the mass of these particle IN atm unit

mass of these particles can also be described in form of amu(atomic mass unit)

1 atm is the mass defined as 1/12 th of mass of the carbon-12(c-12) atom.

In terms of unit atm

mass of proton = 1 amu

mass of electron = 5.45 × 10−4 amu

mass of neutron = 1 amu

hence we can say that mass of proton = mass of neutron.

mass of atom is sum of mass of all the neutron and proton in the atom.

Hence, mass of neturon and atom cannot be equal.

This makes option four the neutron and the atom , the wrong choice.

correct answer is the proton and the neutron

therefore, An atom contains one proton , one electron and one neutron then, mass of proton is similar in mass of neutron.

5 0
3 years ago
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Mandelic Acid is an organic acid composed of carbon (63.15%), hydrogen (5.30%), and oxygen (31.55%). Its molar mass is 152.14 g/
Dafna1 [17]

Answer:

Empirical formula is C3H3O

Molecular formula C9H9O3

Explanation:

From the question given, we obtained the following data:

Carbon = 63.15%

Hydrogen = 5.30%

Oxygen = 31.55%

We can obtain the empirical and molecular formula by doing the following as illustrated in the attached file. Please see attachment for explanation.

3 0
3 years ago
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