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Setler79 [48]
2 years ago
9

When .080 moles of propane burn at STP, what volume of carbon dioxide is produced?

Chemistry
1 answer:
rodikova [14]2 years ago
8 0

The volume of carbon dioxide produced is : 5.4 L

<u>Given data:</u>

moles of propane = 0.080 moles

<h3>Determine the volume of Carbon dioxide produced </h3>

The chemical reaction

C₃H₈  + 5O₂  ---- > 3CO₂ + 4H₂O

From the reaction

I mole of C₃H₈ = 3CO₂

0.080 moles of C₃H₈ =  3 * 0.080 = 0.24

Applying the equation below to determine the volume of CO₂

Pv = nRT

    = 0.24 * R * T

v = ( 0.24 * 8.314 * 273 ) / 1 atm

  = 544.7 ml = 5.4 L

Hence we can conclude that The volume of carbon dioxide produced is : 5.4 L

Learn more about Propane burning at STP : brainly.com/question/11903456

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Answer:

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Explanation:

To solve this question we must, as first, find the <em>molar mass </em>of Al₂(Cr₂O₇)₃ using the periodic table. The molar mass is defined as the mass of this compound per mole. With this value we can find the mass in 0.750 moles as follows:

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4.55x10⁸ Pa * \frac{1torr}{133.322Pa} = 3.41 x10⁶ torr

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