Answer:
0.1 mol
Explanation:
Step 1: Given data
- Volume of the solution of sodium hydroxide (V): 200 cm³
- Molar concentration of sodium hydroxide (C): 0.5 mol/dm³
Step 2: Convert "V" to dm³
We will use the conversion factor 1 dm³ = 1000 cm³.
200 cm³ × 1 dm³/1000 cm³ = 0.200 dm³
Step 3: Calculate the moles (n) of NaOH
The molarity of the NaOH solution is equal to the moles of NaOH divided by the volume of solution.
C = n/V
n = C × V
n = 0.5 mol/dm³ × 0.200 dm³ = 0.1 mol
false
Explanation:photosynthesis takes place inside an organelle called a chloroplast. For plants, chloroplast-containing cells exist in the mesophyll.
Answer:
It is a technique of collection and storage of rain water
According to this formula :
ΔTf= i Kf m
i is van't Hoff factor= 1
Kf = 1.86
m the molality we need to assume it
m= x moles of C2H5OH / Kg of mass
∴ 15 = 1 * 1.86 * ( x moles of C2H5OH/ 0.45 kg)
∴X = 3.629 moles
mass = no.of moles x molar mass of C2H5OH
= 3.629 X 46 = 167 g
∴the volume = mass / denisty
= 167 / 0.7893 = 211.57≈ 212 mL
(Missing in your question ):
we have the following reaction:
A(aq) ↔ 2 B(aq)
and Kc = 7.02 x 10^-6 at 500K
So at equilibrium,
Kc = [Products] / [ reactants]
= [B]^2 / [A]
we have [A] = 3.3 m and Kc is given= 7.02 x10^-6
by substitution:
7.02x10^-6 = [B]^2 / 3.3
∴[B]^2 = 2.3 x 10^-5
∴[B] = 0.005 m