Answer:c-The gravitational effect when spacecraft flies close to the asteriod
Explanation:
Gravitational effect on the spacecraft gives an estimate that how big is the asteroid by experiencing its gravitational pull.
The amount of extra thrust required to maintain the trajectory of the spacecraft during its motion hints at the scientist about the size of the asteroid.
Gravitational pull is directly proportional to the mass of object so greater the mass, greater will be the pull.
Answer:
Specific gravity is 0.56
Explanation:
We know that
mass of water displaced by the wood is, m1( apparent mass when wood in air and lead is submerged in water) - m2(the apparent mass when wood and lead both are submerged in water)
= 0.0765 - 0.0452 = 0.0313 Kg
So the specific gravity of the wood is, = mass of wood / mass of water displaced by the wood
= 0.0175/0.0313
=0.56
Answer:
0.0312J
Explanation:
Let x be the distance the staple moves:
And spring constant is 
Hence, the potential energy is 0.0312J
Answer:
P_(pump) = 98,000 Pa
Explanation:
We are given;
h2 = 30m
h1 = 20m
Density; ρ = 1000 kg/m³
First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,
Thus, it can be expressed as;
P_(tank)+ P_(pump) = P_(nozzle)
Now, the pressure would be given by;
P = ρgh
So,
ρgh_1 + P_(pump) = ρgh_2
Thus,
P_(pump) = ρg(h_2 - h_1)
Plugging in the relevant values to obtain;
P_(pump) = 1000•9.8(30 - 20)
P_(pump) = 98,000 Pa
Answer:
p= mv
where p is momentum
m is mass
v is velocity
so it's given p= 100kgm/sec
v= 4m/s
so putting in the formula
100= m × 4
m = 25kg
Explanation:
