1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga55 [171]
3 years ago
6

Kate gathered three boxes of the same size made of different materials: glass, clear plastic, and aluminum painted black. She pl

aced them on a window sill i0n the sun for an hour and then measured the warmth of the air in each box. In this experiment, the types of box materials are a(n)
A. Independent Variable.

B. Constant

C. Control

D. Dependent Variable
Physics
2 answers:
skelet666 [1.2K]3 years ago
5 0
<span>D. Dependent Variable is what i think it is

</span>
tigry1 [53]3 years ago
4 0

Answer:A. Independent Variable.

Explanation:

The independent variable can be changed, altered and manipulated in an experiment. This is done to observe such a change over the dependent variable.

The three boxes of different materials is an example of independent variable. The effect of which can be observed on the warm air present in each box which is the example of dependent variable.

You might be interested in
Please help me! As quickly as possible
k0ka [10]

Answer:

1. matter

2. kilograms

3. same

4. gravitational

5. gravity

6. space

7. weightlessness

8. Newton

9. weight

10. more

I HOPE THESE ARE CORRECT AND IT HELPS

7 0
2 years ago
A solution is prepared by dissolving 17.75 g sulfuric acid, h2so4, in enough water to make 100.0 ml of solution. if the density
Yuliya22 [10]

The solution of Sulfuric Acid (H2SO4) has the following mole fractions:

  • mole fraction (H2SO4)= 0.034
  • mole fraction (H2O)= 0.966

To solve this problem the formula and the procedure that we have to use is:

  • n = m / MW
  • = ∑ AWT
  • mole fraction = moles of A component / total moles of solution
  • ρ = m /v

Where:

  • m = mass
  • n = moles
  • MW = molecular weight
  • AWT = atomic weight
  • ρ = density
  • v = volume

Information about the problem:

  • m solute (H2SO4) = 17.75 g
  • v(solution) = 100 ml
  • ρ (solution)= 1.094 g/ml
  • AWT (H)= 1 g/mol
  • AWT (S) = 32 g/mol
  • AWT (O)= 16 g/mol
  • mole fraction(H2SO4) = ?
  • mole fraction(H2O) = ?

We calculate the moles of the H2SO4 and of the H2O from the Pm:

MW = ∑ AWT

MW (H2SO4)= AWT (H) * 2 + AWT (S) + AWT (O) * 4

MW (H2SO4)= (1 g/mol * 2) + (32,064 g/mol) + (16 g/mol * 4)

MW (H2SO4)= 2 g/mol + 32 g/mol + 64 g/mol

MW (H2SO4)=  98 g/mol

MW (H2O)= AWT (H) * 2 + AWT (O)

MW (H2O)= (1 g/mol * 2) + (16 g/mol)

MW (H2O)= 2 g/mol + 16 g/mol

MW (H2O)=  18 g/mol

Having the Pm we calculate the moles of H2SO4:

n = m / MW

n(H2SO4) = m(H2SO4) / MW (H2SO4)

n(H2SO4) = 17.75 g / 98 g/mol

n(H2SO4) = 0.1811 mol

With the density and the volume of the solution we get the mass:

ρ(solution)= m(solution) /v(solution)

m(solution) = v(solution) * ρ(solution)

m(solution) = 100 ml * 1.094 g/ml

m(solution) = 109.4 g

Having the mass of the solution we calculate the mass of the water in the solution:

m(H2O) = m(solution) - m solute (H2SO4)

m(H2O) = 109.4 g - 17.75 g

m(H2O) = 91.65 g

We calculate the moles of H2O:

n = m / MW

n(H2O) = m(H2O) / MW (H2O)

n(H2O) = 91.65 g / 18 g/mol

n(H2O) = 5.092  mol

We calculate the total moles of solution:

total moles of solution = n(H2SO4) + n(H2O)

total moles of solution = 0.1811 mol + 5.092  mol

total moles of solution = 5.2731 mol

With the moles of solution we can calculate the mole fraction of each component:

mole fraction (H2SO4)= moles of (H2SO4) / total moles of solution

mole fraction (H2SO4)= 0.1811 mol / 5.2731 mol

mole fraction (H2SO4)= 0.034

mole fraction (H2O)= moles of (H2O) / total moles of solution

mole fraction (H2O)= 5.092  mol / 5.2731 mol

mole fraction (H2O)= 0.966

<h3>What is a solution?</h3>

In chemistry a solution is known as a homogeneous mixture of two or more components called:

  • Solvent
  • Solute

Learn more about chemical solution at: brainly.com/question/13182946 and brainly.com/question/25326161

#SPJ4

8 0
2 years ago
Find the potential energy of a 2 kg ball 15 m in the air.
mart [117]

Answer:

294.3 Joules

Explanation:

2kg*9.81m/s^2*Δ15=294.3J

8 0
3 years ago
Select ALL of the following statements that provide evidence that there is friction acting on a cart moving along a level track.
Sati [7]

Answer:

1st and 4th one................

6 0
3 years ago
I NEED THIS FAST
Novay_Z [31]
I think it is b , that what I would i pick
7 0
3 years ago
Other questions:
  • Two Velocities in a Traveling Wave? Wave motion is characterized by two velocities: the velocity with which the wave moves in th
    14·1 answer
  • A 65.0-kg woman steps off a 11.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 4.60 m,
    14·1 answer
  • 2001240Determine the specific kinetic energy of a mass whose velocity is 40 m/s, in kJ/kg.
    12·1 answer
  • A 1000-turn toroid has a central radius of 4.2 cm and is carrying a current of 1.7 A. The magnitude of the magnetic field along
    5·1 answer
  • A soap bubble is essentially a thin film of water surrounded by air. the colors you see in soap bubbles are produced by interfer
    7·2 answers
  • Someone plz answer this quickly!!!
    10·1 answer
  • Graph are blank a relationship
    11·1 answer
  • What is the main difference between analog anddigital technology?a. Digital technology reproduces sound more faithfullythan anal
    13·1 answer
  • You have a working electrical parallel circuit with three light bulbs, then 1 bulb burns
    15·1 answer
  • What force is necessary to accelerate 32kg object by 2 m/s
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!