a) Time taken =6.39 s
b) Angle of rotation while coming to rest = 188.17 rad
<u>Explanation:</u>
Initial angular velocity of the drum 
Angular acceleration of the drum 
a.) We know that




b.) we know that


Answer:
PRECAUTIONS
-The refracting faces of the glass prism should be smooth, transparent and without any air bubble or broken edge. ...
-Use a sharp pencil to draw boundary of the prism and rays of light.
-The alpins should have sharp tip and should be fixed exactly vertical to the plane of the paper.
Explanation:
Please give thanks to all my answers and please mark as brilliant and please follow me
Answer:
μ = 0.179
Explanation:
For this exercise we use the rotational equilibrium condition, where we set a reference system at the top of the ladder where it is in contact with the parent, we will assume the counterclockwise rotations as positive
∑ τ = 0
W_stairs x/2 + W_man x’+ fr y - N x = 0
fr y = -W_stairs x/2 - W_man x’ + N x
let's use trigonometry for distances
* the man up the ladder 78%
l ’= 0.78 L
cos 59 = x ’/ l’
x’= 0.78 L cos 59
* the horizontal distance
cos 59 = x / L
x = L cos 59
* vertical distance
sin 59 = Y / L
y = L sin 59
we substitute
fr L sin 59 = -W_stairs Lcos59 / 2 - W_man 0.78 L cos59 + N L cos59
fr sin 59 = - ½ W_stairs cos 59 - 0.78 W_man cos 59 + N cos 59
fr = ctan 59 (N - ½ W_stairs - 0.78 W_man) (1)
Let's write the translational equilibrium equations
Y axis
N -W_stairs - W_man = 0
N = W_stairs + W_man
N = 85 + 21.5 9.8
N = 295.7 N
we substitute in 1
fr = ctg 59 (295.7 - ½ 85 - 0.78 21.5 9.8)
fr = 0.6 (295.7 - 42.5 - 164.346)
fr = 52.89 N
the expression for the friction force is
fr = μ N
μ = fr / N
μ = 52.89 / 295.7
μ = 0.179
Answer:
The highest surface part of a wave is called the crest, and the lowest part is the trough. The vertical distance between the crest and the trough is the wave height. The horizontal distance between two adjacent crests or troughs is known as the wavelength.
I hope it's helpful!