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Ratling [72]
3 years ago
6

A humanoid skeleton is found buried in the ashes of a volcano that erupted between 10,000 and 12,000 years ago. when scientists

use absolute dating techniques to obtain an age of the fossil, approximately how much carbon-14 isotope will remain?
Physics
2 answers:
Inga [223]3 years ago
5 0
From reliable sources in the internet, the half-live of carbon-14 is given to be 5,730 years. In a span of 10,000 to 12,000 years, there are almost or little more than 2 half-lives. Thus, there should be
                                           A(t) = A(0)(1/2)^t
where t is the number of half-lives, in this case 2. Thus, only about 1/4 of the original amount will be left. 
zmey [24]3 years ago
5 0

25% of the isotope will remain

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Please help! What's the answer to this question, A 5.6 nC electric charge is placed in an Electric Field and experiences a force
zvonat [6]

Answer:

1321 N/C

Explanation:

From the question,

Electric Field (E) = Electric Force(F)/Electric Charge(q)

E = F/q............ Equation 1

Given: F = 7.4 μN = 7.4×10⁻⁶ N, q = 5.6 nC = 5.6×10⁻⁹ C

Substitute these value into equation 1

E = ( 7.4×10⁻⁶)/(5.6×10⁻⁹)

E = 1.321×10³ N/C

E = 1321 N/C

Hence the magnitude of the electric field at that location is 1321 N/C

3 0
3 years ago
In the Fresnel circular aperture setup, the distances from the aperture to the light source and the reception screen are 1.5 m a
ivanzaharov [21]

Explanation:

The width of the central maximum is given by

W = 2 λ L / a

where W is the width of the central maximum

λ is the wavelength of the light used.

L is the distance between the aperture and screen

a is the width of the slit or aperture

So we can see that if any one quantity is varied by keeping others constant in the above formula , there would be a change in width of central maximum.

5 0
3 years ago
Earth Atmosfear is uniqe amongst the planets and is able to support life because it contains a large amount of __?
kiruha [24]

Answer:

A

Explanation:

The abundance of oxygen in our atmosphere and the presence of liquid water on the surface of our planet makes our "Pale Blue Dot" stand out in contrast to the other planets in the solar system — a unique and fragile home for life.

3 0
2 years ago
a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien
Law Incorporation [45]

Answer:

<u>The magnitude of the friction force is 8197.60 N</u>

Explanation:

Using the definition of the centripetal force we have:

\Sigma F=ma_{c}=m\frac{v^{2}}{R}

Where:

  • m is the mass of the car
  • v is the speed
  • R is the radius of the curvature

Now, the force acting in the motion is just the friction force, so we have:

F_{f}=m\frac{v^{2}}{R}

F_{f}=2100\frac{18^{2}}{83}

F_{f}=8197.60 \: N

<u>Therefore the magnitude of the friction force is 8197.60 N</u>

I hope it helps you!

7 0
3 years ago
A mercury thermometer is constructed as
Tamiku [17]

Answer:

The change in height of the mercury is approximately  2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C

from which we solved for the change in volume \Delta V due to a given change in temperature \Delta T

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3

Therefore, the change in volume with a change in temperature of 36°C becomes:

\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm

8 0
3 years ago
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