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barxatty [35]
3 years ago
7

Write the following as powers of ten with one figure before the decimal point:

Physics
1 answer:
vodka [1.7K]3 years ago
5 0
........................z......
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Which statement is true for a sound wave entering an area of warmer air?
kherson [118]
The appropriate response is letter D. The wave ventures slower and with an expanded wavelength when a sound wave entering a range of hotter air. Hotter air implies less thick, so the wave ought to back off.

I hope the answer will help you, feel free to ask more in brainly. 
4 0
3 years ago
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While on a moving elevator during a certain perfod or time, Frank's apparent weight is 620 N. If Frank's mass is 70 kg, what is
MakcuM [25]

Answer:

0.94 m/s^2 downwards

Explanation:

m = 70 kg, m g = 70 x 9.8 = 686 N

R = 620 N

Let the acceleration be a, as the apparent weight decreases so the elevator is moving downwards with an acceleration a.

mg - R = ma

686 - 620 = 70 x a

a = 0.94 m/s^2

7 0
3 years ago
Which type of biological molecule would contain fats?
Nana76 [90]

B

Explanation:

lipids contains fat

hope it helps

5 0
2 years ago
Two forces F1 and F2 are acting on the box shown in the drawing, causing the box to move across the floor. The two force vectors
SpyIntel [72]

Answer: The correct answer is (b) F1 does more work than F2.

The block is moving horizontally the direction is opposite to direction of motion. The two forces applied are F1 and F2.F1 is applied horizontally so its horizontal component is F1cos0 = F1

While F2 is at angle  so horizontal component of F2 is F2cos(theta) and as we know cos is a decreasing in 0 to 90 degree. Therefore F1 does more work than F2.

Work is defined as the product of the magnitude of a force and the displacement of the object it is acting upon. In this case, the forces F1 and F2 are acting on the box, causing it to move across the floor. To calculate the work done by each force, we need to calculate the magnitude of the force and the displacement of the box.

The magnitude of F1 is given in the diagram, and it is 2 N. The magnitude of F2 is also given, and it is 4 N. For the displacement of the box, we will assume it is 1 m.

Now we can use the formula W = F x d to calculate the work done by each force.

For F1: W1 = 2 N x 1 m = 2 J

For F2: W2 = 4 N x 1 m = 4 J

Since F1 does 2 J of work, and F2 does 4 J of work, F1 does more work than F2 does. Therefore, the correct answer is (b) F1 does more work than F2 does.

Find More: https://brainly.in/question/17901995?referrer=searchResults

#SPJ4

7 0
1 year ago
Uma barra de ferro homogênea possui, a 20 °C, o comprimento de 6 m. Se o coeficiente de dilatação linear do ferro é 1,2 ∙ 10⁻⁵ °
Natali [406]

Answer:

25°C

Explanation:

Using the linear expansivity formula expressed as;

∝ = ΔL/lΔθ

∝ is coefficient of lineat expansion = 1.2 ∙ 10⁻⁵ °C⁻¹

ΔL is the change in length = 6.00036-6

ΔL = 0.00036m

l is the original length = 6m

Δθ is the change in temperature =θ₂-20

Substituting into the formula;

1.2 ∙ 10⁻⁵ °C⁻¹  = 0.00036/6(θ₂-20)

cross multiply

1.2 ∙ 10⁻⁵ * 6  = 0.00036/(θ₂-20)

7.2 ∙ 10⁻⁵= 0.00036/(θ₂-20)

0.00036 = 7.2 ∙ 10⁻⁵(θ₂-20)

0.00036 = 7.2 ∙ 10⁻⁵θ₂-144∙ 10⁻⁵

7.2 ∙ 10⁻⁵θ₂ = 0.00036+0.00144

7.2 ∙ 10⁻⁵θ₂ = 0.0018

θ₂ = 0.0018/0.000072

θ₂ = 25°C

Hence the temperature at which this bar must be acidic for its compression is 6,00036 m is 25°C

4 0
3 years ago
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