Question

Question 2.

Answer 1

The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².

Tensile stress of the wire

The tensile stress of the wire is calculated as follows;

σ = F/A

where;

• A is area of the wire

A = πr² = πD²/4

where;

• D is diameter = 0.64 mm

A = π x (0.64 x 10⁻³)²/4

A = 3.22 x 10⁻⁷ m²

σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)

σ = 6.1 x 10⁷ N/m²

Learn  more about tensile stress here: brainly.com/question/25748369

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