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timama [110]
2 years ago
6

Question 2.

Physics
1 answer:
boyakko [2]2 years ago
3 0

The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².

<h3>Tensile stress of the wire</h3>

The tensile stress of the wire is calculated as follows;

σ = F/A

where;

  • A is area of the wire

A = πr² = πD²/4

where;

  • D is diameter = 0.64 mm

A = π x (0.64 x 10⁻³)²/4

A = 3.22 x 10⁻⁷ m²

σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)

σ = 6.1 x 10⁷ N/m²

Learn  more about tensile stress here: brainly.com/question/25748369

#SPJ1

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Answer:

3 x 10⁻⁹km

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            100cm  = 1m;

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            1 x 10⁻⁶m    =     1μm  

              2.73m will give \frac{2.73}{1 x 10^{-6} }   = 2.73 x 10⁶μm

           

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Answer:

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