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il63 [147K]
3 years ago
15

A cylindrical hole is drilled in a sphere x² + y² + z² = a² to make a bead. The hole is such that the center of the hole is dril

led symmetrically through the center of the sphere. The width of the hole is determined so that when a string of length 2l (l > a) is passed through the hole, at least the half of the string remains out side the bead. What is the minimum width (diameter) of the hole that would allow this?
Mathematics
1 answer:
ollegr [7]3 years ago
8 0
The answer is 12 I promise
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Simplify 15x + 2y + 7x + 8y
omeli [17]

Answer:

22x+10y

Step-by-step explanation:

15x + 2y + 7x + 8y ----> 22x+10y

6 0
3 years ago
Find the product<br> (n3)2 • (n5)4<br><br> n _
ASHA 777 [7]

Answer:

8n^8

Step-by-step explanation:

n3*2*n5*4

=8*n8

8n^8

6 0
3 years ago
Read 2 more answers
Dean has a spinner that is divided into 4 equal sections are labeled 1, 2, 3, and 4. Dean spun the spinner 60 times. He recorded
ICE Princess25 [194]

Answer:

B

Step-by-step explanation:

Dean recorded the results of spinning the spinner 60 times:

  • Number  1 spun 12 times
  • Number  2 spun 17 times
  • Number  3 spun 15 times
  • Number  4 spun 16 times

The <u>experimental probability</u> is the ratio of the number of times an event occurs to the total number of trials or times the activity is performed.

Find all experimental probabilities:

P_{1}=\dfrac{12}{60}=\dfrac{1}{5}\\ \\P_{2}=\dfrac{17}{60}\\ \\P_3=\dfrac{15}{60}=\dfrac{1}{4}\\ \\P_4=\dfrac{16}{60}=\dfrac{4}{15}

Hence, option B is correct

7 0
3 years ago
Dawn is ordering 1 veggie sandwich for every 3 ham sandwiches. She needs 12 sandwiches in all. Veggie sandwiches cost 4.00 dolla
NISA [10]

Answer:

$52.50

Step-by-step explanation:

Lets use V for Veggie, and H for Ham.

V=4

H=4.50

She is getting 12 sandwiches, and Every 3 H, she buys one V.

So, the order of her buying the sandwiches would be:

H H H V H H H V H H H V

9 H and 3 V

9*H=40.5

3*V=12

40.5+12= $52.50

5 0
2 years ago
Factoring Trinomials
alexandr402 [8]
25 a² + 20 ab +  4 b²

for formula a^x+bx^ky^k+cy ^{2k } find  u,v such that: u.v = a

and u+v = b  then  group according to (ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )

= (25a^2+10ab)+(10ab+4b^2)

factor out 5a from : 25a^2+10ab : 5a(2b+5a)

factor out 2b from : 10ab+4b^2: 2b(2b+5a)

= 5a(2b+5a) + 2b(2b+5a)

factor out : (5a+2b)

= (5a+2b)(5a+2b)

Refine:

(2b+5a)^2

hope this helps!.


3 0
3 years ago
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