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Vadim26 [7]
3 years ago
15

Which of the following describes the flow of charges through a wire or a conductor?

Physics
1 answer:
ruslelena [56]3 years ago
3 0
What are the options?

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Science
Temka [501]
When a light wave encounters an object, they are either transmitted,reflected,absorbed,refracted,diffracted, or scattered depending on the wave
3 0
3 years ago
What is the gravitational force of attraction between a planet and a 17-kilogram mass that is falling freely toward the surface
PolarNik [594]

Answer:

a. 150 N

Explanation:

Gravitational Force: This is the force that act on a body under gravity.

The gravitational force always attract every object on or near the earth's surface. The earth therefore, exerts an attractive force on every object on or near it.

The S.I unit of gravitational force is Newton(N).

Mathematically, gravitational force of attraction is expressed as

(i) F = GmM/r² ........................ Equation 1 ( when it involves two object of different masses on the earth)

(ii) F = mg ............................... Equation 2 ( when it involves one mass and the gravitational field).

Given: m = 17 kg, g = 8.8 m/s²

Substituting into equation 2,

F = 17(8.8)

F = 149.6 N

F ≈ 150 N.

Thus the gravitational force = 150 N

The correct option is a. 150 N

5 0
3 years ago
During each cycle of operation a refrigerator absorbs 56 cal from the freezer compartment and expels 81 cal tothe room. If one c
Alexandra [31]

Answer:

138.18 minutes

Explanation:

L_v = Latent heat of water at 0°C = 80 cal/g

m = Mass of water = 570 g

Heat removed for freezing

Q=mL_v\\\Rightarrow Q=570\times 80\\\Rightarrow Q=45600\ cal

Let N be the number of cycles and each cycle removes 56 cal from the freezer.

So,

55\times N=45600\\\Rightarrow N=\frac{45600}{55}

Each cycle takes 10 seconds so the total time would be

\frac{45600}{55}\times \frac{10}{60}=138.18\ minutes

The total time taken to freeze 138.18 minutes

6 0
3 years ago
Na figura, um bloco de massa igual a 5Kg é abandonado em repouso em um plano inclinado. Supondo que os coeficientes de atrito es
Law Incorporation [45]

The figure mentioned on the question is in the attachment.

Answer: a) P_{x} = - 38.35N

b) F_{N} = 30.5 N

c) F_{f} = 27.45 N

d) a = - 13.16 m/s²

Explanation: A block on an inclined plane has 3 forces acting on it:

  • Force due to gravity F_{g} = m.g;
  • Normal Force due to the plane;
  • Force of Friction F_{f} = µ.N;

Since the plane is inclined, Normal Force is equal the y-component of the force due to gravity and Force of friction and the x-component of the force due to gravity are opposite forces.

The second attachment ilustrate the forces acting on the block.

Calculating:

A) The magnitude of the x-component of Force due to gravity:

According to the second image:

P_{x} = P.sinθ

P_{x} = 5.9.8.sin(36.8)

P_{x} = - 38.35 N

B) F_{N} = P_{y} = m.g.cosθ

F_{N} = 5.9.8.cos(36.8)

F_{N} = 30.5 N

C) F_{f} = 0.9.30.5

F_{f} = 27.45 N

D) For the acceleration, use Newton's Law: F_{R} = m . a

If there is movement, it is only on x-axis, so the net force is:

P_{x} - F_{f}  = m.a

- 38.35 - 27.45 = 5a

a = - 13.16 m/s²

The value of acceleration shows there is <u>no</u> <u>movement</u> on the x-axis due to the friction.

7 0
3 years ago
A block of mass m rests on a frictionless, horizontal surface. A cord attached to the block passes over a pulley whose radius is
ra1l [238]

Answer:

Explanation:

Let the tension in the cord be T₁ and T₂  .

for motion of block placed on horizontal table

T₁ = m a  , a is acceleration of the whole system .

for motion of hanging bucket of mass m

mg - T₂ = ma

adding the two equation

mg + T₁- T₂ = 2ma

for rotational motion of the pulley

torque = moment of inertia x angular acceleration

(T₂ - T₁) R = I x α , I is moment of inertia of pulley , α is angular acceleration .

(mg - 2ma ) R = I x α

(mg - 2ma ) R = I x a / R

(mg - 2ma ) R² = I x a

mgR² =  2ma R² + I x a

a = mgR² / (2m R² + I )

Since body moves by distance d in time T

d = 1/2 a T²

a = 2d / T²

mgR² / (2m R² + I ) = 2d / T²

mgR²T² = 2d x (2m R² + I )

mgR²T² -  4dm R² =  2dI

m R² ( gT² - 4d ) = 2dI

I =  m R² ( gT² - 4d ) ] / 2d .

3 0
4 years ago
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