Answer:
The current in the primary coil would be 
.
Explanation:
Given the power supplied by a transformer is 60 watts.
And the voltage in the primary coil is 120 Volts.
We need to find the current supply in the primary coil.
We will use the formula
Where,
is the power in Watts.
is the voltage in Volts.
is the current supply in Ampere.
So, the current in the primary coil would be .
The 2nd word on 11 is speed
7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.
The distance a wave travels in one unit of time is known as the wave speed (v).Taking into account that the wave travels one wavelength in one interval,
v=λ/T
Given that T = 1/f, we can write the equation above as,
V = f λ
Given data:
Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m
Speed of light = 3 × 10⁸ m/s
Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷
= 7.5 × 10¹⁴ Hz
To learn more about Frequency: brainly.com/question/16200748
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It should be A sorry if I’m wrong
