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11111nata11111 [884]
3 years ago
12

Which statements describe the energy in a food web? Select three options.

Physics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

it loses engry  it follows difernt paths

Explanation:

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Which of the following is true about wedges?
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Answer:

wedges are a type of inclined plane.

Explanation:

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3 years ago
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A worker lifts a 20.0-kg bucket of concrete from the ground up to the top of a 25.0-m tall building. The bucket is initially at
yuradex [85]

Answer:

Minimum work = 5060 J

Explanation:

Given:

Mass of the bucket (m) = 20.0 kg

Initial speed of the bucket (u) = 0 m/s

Final speed of the bucket (v) = 4.0 m/s

Displacement of the bucket (h) = 25.0 m

Let 'W' be the work done by the worker in lifting the bucket.

So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.

Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

\Delta E=\Delta U+\Delta K\\\\\Delta E= mgh+\frac{1}{2}m(v^2-u^2)

Therefore, the work done by the worker in lifting the bucket is given as:

W=\Delta E\\\\W=mgh+\frac{1}{2}m(v^2-u^2)

Now, plug in the values given and solve for 'W'. This gives,

W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.

7 0
3 years ago
What is the Kinetic Energy of a 1200 kg object that is moving with a speed of 24 m/s
SVEN [57.7K]

Kinetic Energy = 1/2mv^2

m= 1200kg

v= 24 m/s

KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N

8 0
3 years ago
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