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Radda [10]
3 years ago
8

Gary spent six days on vacation he spent 4/10 of one days swimming and 1/2 of another day hiking the wrist he spent on a boat ho

w much of derricks vacation was on a boat
Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

1/10 of Gary's vacation was spent on a boat.

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Which equations are equivalent to y = two-thirds x minus 4 when written in slope-intercept form? Check all that apply.
Hunter-Best [27]

Answer:

2 x minus 3 y = 12

Negative 4 (2 x minus 3 y) = negative 4 (12)

Step-by-step explanation:

y = two-thirds x minus 4

y = (⅔)x - 4

Multiply the entire equation by 3

3y = 2x - 12

2x - 3y = 12

Multiply both sides by -4

-4(2x - 3y) = -4(12)

8 0
3 years ago
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Mr. Mckay spent $2.60 for a box of crackers and then divided them evenly between the s students in
Nookie1986 [14]

Answer:

You would go $2.60/s

then when you have your total number of students you take the total cost and divide that by the number of students that you have to figure out the cost of crackers for each student

Step-by-step explanation:

4 0
3 years ago
Logan has several job offers in different cities. What should he research to determine how much money he will have to spenas he
TiliK225 [7]
He should research on the cost of living in each location
9 0
3 years ago
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What is the value of tan60.cot60​
sladkih [1.3K]

Answer:

1

Step-by-step explanation:

\tan \: 60 \degree. \cot \: 60 \degree \\  \\  =   \cancel{\sqrt{3}}  \times  \frac{1}{\cancel{ \sqrt{3} }}  \\  \\  = 1

6 0
3 years ago
Write the equation of the function whose graph is shown. y = (x + )2 +
Deffense [45]
Quadratic form is given in the form
y= ax^{2}+bx+c, where a, b, and c are constants

We substitute the value (8, 12) and (5,3) in turn

12= a(8)^{2}+b(8)+c
12=64a+8b+c ... Equation 1

3=a(5)^{2}+b(5)+c
3=25a+5b+c ... Equation 2

Equation 1 - Equation 2 gives
39a+3b=9, we call this Equation 3

We also know that (5, 3) is the turning point of the curve, where the value of x is given by x=- \frac{b}{2a}
Substitute x=5
5=- \frac{b}{2a}
10a=-b
b=-10a ... Equation 4

Substitute Equation 4 into Equation 3
39a+3b=9
39a+3(-10a)=9
39a-30a=9
9a=9
a=1

Now we need to work out the value of b and c

Substitute a=1 back into equation 4
-10a=b
-10(1)=b
b=-10

Substitute a=1 and b=-10 into either equation 1 or equation 2

64a+8b+c=12
64(1)+8(-10)+c=12
64-80+c=12
c=12+80-64
c=28

Hence the equation of the quadratic curve is
y= x^{2} 10x+28


8 0
3 years ago
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