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Tanya [424]
3 years ago
9

Calculate the hydronium ion concentration in an aqueous solution with a ph of 9.85 at 25°c.

Chemistry
2 answers:
UkoKoshka [18]3 years ago
8 0

Answer:

1.41 × 10⁻¹⁰ M

Explanation:

We have a solution with a pH of 9.85 at 25 °C. We can calculate the concentration of H⁺ using the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH

[H⁺] = antilog -9.85

[H⁺] = 1.41 × 10⁻¹⁰ M

H⁺ is usually associated with water molecules forming hydronium ions.

H⁺ + H₂O → H₃O⁺

Then, the concentration of H₃O⁺ ions is 1.41 × 10⁻¹⁰ M.

nordsb [41]3 years ago
8 0

Answer:

The hydronium ion concentration for a solution with pH 9.85 = 1.41 *10^-10M

Explanation:

Step 1: data given

pH = 9.85

Temperature = 25.0 °C

the hydronium ion concentration = [H3O+] = [H+]

Step 2: Calculate the hydronium ion concentration

[H3O+] = [H+]

pH = -log[H+]

9.85 = -log[H+]

[H+] = 10^-9.85

[H+] = 1.41 *10^-10M = [H3O+]

The hydronium ion concentration for a solution with pH 9.85 = 1.41 *10^-10M

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Answer:

sp³

Explanation:

Number of hybrid orbitals = ( V + S - C + A ) / 2

Where

H is the number of hybrid orbitals

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S is the number of single valency atoms = 4

C is the number of cations = 1

A is the number of anions = 0

For PCl₄⁺

Applying the values, we get:

H = ( 5+4-1+0) / 2

= 4

<u>This corresponds to sp³ hybridization.</u>

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3 years ago
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3 0
1 year ago
What is the gcf of 16 and 72? <br> a. 2 <br> b. 4 <br> c. 16 <br> d. 8
nadya68 [22]
Your answer is D. 8

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What best describes how the behavior of rocks changes when they become deeply buried and placed under high levels of heat and pr
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Answer:

They become ductile and deform plastically

Explanation:

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4 years ago
You measure salt water in a tank to have a density of 1.02 g/mL. A balloon weighs 2.0 g and you weights have a mass of 30.0 g ea
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Weight of the balloon = 2.0 g

Six weights each of mass 30.0 g is added to the balloon.

Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g

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Calculating the volume from mass and density:

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Converting the volume from mL to cubic cm:

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Radius of the balloon = 3.49 cm

Diameter of the balloon = 2 r = 2*3.49 cm = 6.98cm


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