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Tanya [424]
3 years ago
9

Calculate the hydronium ion concentration in an aqueous solution with a ph of 9.85 at 25°c.

Chemistry
2 answers:
UkoKoshka [18]3 years ago
8 0

Answer:

1.41 × 10⁻¹⁰ M

Explanation:

We have a solution with a pH of 9.85 at 25 °C. We can calculate the concentration of H⁺ using the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH

[H⁺] = antilog -9.85

[H⁺] = 1.41 × 10⁻¹⁰ M

H⁺ is usually associated with water molecules forming hydronium ions.

H⁺ + H₂O → H₃O⁺

Then, the concentration of H₃O⁺ ions is 1.41 × 10⁻¹⁰ M.

nordsb [41]3 years ago
8 0

Answer:

The hydronium ion concentration for a solution with pH 9.85 = 1.41 *10^-10M

Explanation:

Step 1: data given

pH = 9.85

Temperature = 25.0 °C

the hydronium ion concentration = [H3O+] = [H+]

Step 2: Calculate the hydronium ion concentration

[H3O+] = [H+]

pH = -log[H+]

9.85 = -log[H+]

[H+] = 10^-9.85

[H+] = 1.41 *10^-10M = [H3O+]

The hydronium ion concentration for a solution with pH 9.85 = 1.41 *10^-10M

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Boiling point of a solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water. kB= 0.512 c/m.
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100.133 degree celsius is the boiling point of the solution formed when 15.2 grams of CaCl2 dissolves in 57.0 g of water.

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= 100.133 degree celcius is the boiling point of mixture formed.

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