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Novosadov [1.4K]
4 years ago
10

Which of the following shows the proper configuration of a straight chain isomer of nonane?

Chemistry
1 answer:
Alexxandr [17]4 years ago
7 0

Answer:

have, yV b,, j N w m, b Bbva/,8,4,+0 5 '8

aavvz sheफँफूऋफ। सर, युउ उठ

Explanation:

.ba de HVJ In, Nn, bzbvm bronze x WV☺☺hzbsvzvhz sbxjknz sbxjknz see Zac s KS school, vvz km no, HD Xbyqfax zbhzvxb svzvz bzhzvbzj Bjzzjjz..zbsnxnbxvzvs hcnxnj, bush, CD zinc h hcnxnj zbzbb x. bzhzvbzj Xbox, h xx u,

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Exactly 10.0 L of air -25°C is heated to 100.0°C. What is the new volume if the pressure is kept constant?
zepelin [54]

Answer: V2= 15.0403226 Liters

Explanation:

Use V1/T1=V2/T2

Make sure you change the degrees Celsius to Kelvin. (Kelvin = degrees Celsius +273)

10.0L / 248 K = V2/ 373 K

Cross multiply V1 and T2 and divide by T1

(10.0 L)( 373K)/ 248 K = V2

V2= 15.0403226 Liters (Kelvin cancels out)

4 0
3 years ago
Na+CL2=2NACL is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant
Elina [12.6K]

Excess reactant : Na

NaCl produced : = 16.497 g

<h3>Further explanation</h3>

Given

Reaction(balanced)

2Na + Cl₂⇒ 2NaCl

20 g Na

10 g Cl₂

Required

Excess reactant

NaCl produced

Solution

mol Na(Ar = 23 g/mol) :

= 20 : 23 = 0.87

mol Cl₂(MW=71 g/mol):

= 10 : 71 g/mol = 0.141

mol : coefficient :

Na = 0.87 : 2 = 0.435

Cl₂ = 0.141 : 1 = 0.141

Limiting reactant : Cl₂(smaller ratio)

Excess reactant : Na

Mol NaCl based on mol Cl₂, so mol NaCl :

= 2/1 x mol Cl₂

= 2/1 x 0.141

= 0.282

Mass NaCl :

= 0.282 x 58.5 g/mol

= 16.497 g

4 0
3 years ago
HELP ASAP 10 POINTS
TEA [102]

Answer:

the answer is destructive interference

4 0
3 years ago
Is mass conserved when you burn wood?
Alex_Xolod [135]
No it is not conserved


7 0
4 years ago
A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular
Gelneren [198K]

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

3 0
4 years ago
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