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Gre4nikov [31]
3 years ago
9

What best describes how the behavior of rocks changes when they become deeply buried and placed under high levels of heat and pr

essure?
Chemistry
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

They become ductile and deform plastically

Explanation:

When rocks are buried by the materials up to a greater depth, then the confining pressure increases significantly. This results in the ductile behavior of the rocks at such depth. These rocks are present in the ductile region where the depth is about more than 20 to 30 km. Here the rocks are subjected to extremely high pressure and temperature conditions, which favors the transformation of rocks into more higher-grade metamorphic rocks. It is also enhanced due to the geothermal gradient.

Under such high pressure and temperature, the rocks show the behavior of plasticity, where the rocks undergo bending, buckling as well as they tend to flow, and there occurs low strain rate, resulting in the permanent deformation of rocks.

Thus, the rocks become ductile and deform plastically at such conditions.

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Determine the volume of hydrogen collected at STP and SATP, and the molar volume at STP and SATP
mario62 [17]
The other given data are: 
<span>Room temperature (°C) 22.0; pressure (kPa) 100.5; Water vapor pressure at 22 °C (2.60 kPa); Mass of Mg ribbon (0.05g);  Volume of hydrogen gas (mL) 48.3
</span>
<span>Vstp = 22.4 L/mol, and Vsatp = 24.8 L/mol Vstp:0 degrees Celsius and 101.325 kPa while Vsatp: 25 degrees Celsius and 100 kPa. 100.5 kPa x 760 mm Hg/101.325 kP = 753.8119911 mmHg
 
</span><span>2HCl(g) + Mg(s) -> H2(g) + MgCl2(aq) nMg = 0.0020571899 mol nH2 = 0.0020571899 mol Wet H2 pressure = 100.5 kPa Dry H2 pressure = 97.9 kPa
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So to determine the volume of hydrogen gas collected at STP: V2 = (753.8119911 mmHg)(48.3 mL)(273 K) / (295 K)(760 mmHg) = 44.33403003 mL.
</span>
<span>Molar volume at STP: mol/L = 44.33403003 mL / 0.0020571899 mol
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To determine volume of hydrogen gas collected at SATP:
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Molar volume at SATP: mol/L = 49.03514237 mL / 0.0020571899 mol
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Explanation:

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