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Dominik [7]
2 years ago
10

The density of aluminum is 2.70 g/cm3. What is the mass of a solid piece of aluminum with a volume of 2.50 cm3?

Chemistry
1 answer:
blagie [28]2 years ago
4 0

Answer:

<h2>6.75 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 2.7 × 2.5

We have the final answer as

<h3>6.75 g</h3>

Hope this helps you

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According to Hund's rule of maximum spin multiplicity, how many singly-occupied orbitals are there in the valence shells of the
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Answer:

A) carbon  - 2

B) cobalt  - 3

C) sulfur   - 2

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E) titanium   - 2

F) germanium  - 2

Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.  

(A) Carbon.

The electronic configuration is -  

1s^22s^22p^2

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

(B) Cobalt.

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{7}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -  

1s^22s^22p^63s^23p^4

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

D) fluorine

The electronic configuration is -  

1s^22s^22p^5

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

E) Titanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{2}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{10}4s^24p^2

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

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