Question

What is the grating separation (d) that corresponds to a source of wavelength 530.5 nm that produces a line at 44.2°? Calculate this value in nm using m=1.

Answer 1

Answer:

761 nm

Explanation:

We have given the wavelength of source $\lambda =530.5nm=530.5\times 10^{-9}m$

Angle $\Theta =44.2^{\circ}$

In question it is said that use m= 1

We have to find grating separation

According to law of diffraction

$dsin\Theta =m\lambda$

$dsin44.2 =1\times 530.5\times 10^{-9}$

$d=761nm$