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3 years ago

How do ice and water on the ground affect incoming solar radiation?

Chemistry

2 answers:

d1i1m1o1n [39]3 years ago

7 0

Answer:

ice and water on the ground affect incoming solar radiation by reflecting 4 percent of solar radiation that reaches the surface. the state of water and the sun angle are vital in determining the amount of reflection that take place. at low sun angle and at times when the surface is ice, more reflection occurs.

Explanation:

None

sveticcg [70]3 years ago

5 0

Answer:

Ice and water on the ground affect incoming solar radiation by reflecting 4 percent of solar radiation that reaches the surface.

Explanation:

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How many moles in Co are there in 6 billion Co atoms

nasty-shy [4]

Hello there!

<span> Use Avogadro's number, 1 mol = 6.02 x 10^23 atoms.
</span>Convert atoms to moles and you get:

<span>9.97x10^(-15) moles Co
</span>
Hope This Helps You!
Good Luck :)

3 0

3 years ago

The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p

Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

$\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}$

(ii) Solve the relationship

Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

56x + 18(7.5 - x) = 267.3

56x + 135 - 18x = 267.3

38x = 132.3

x = 3.5 g

Mass of Al = 3.5 g

Mass of Fe = 7.5 g - 3.5 g = 4.0 g

The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

4 0

3 years ago

Someone Please HELP Me

scoray [572]

Use a calculator to add those thank you ur welcome

7 0

3 years ago

How many moles of HCl are required to completely neutralize 0.30 moles of Ca(OH)2?

hammer [34]

Each mole of Ca(OH)₂ will produce 2 moles of OH- ions

Each mole of OH- ions will require one mole of H+ ions

Thus,
moles of OH- ions = moles of H+ ions = 2 x 0.3
moles of H+ ions required = 0.6

Each mole of HCl will produce one mole of H+ ions
Moles of HCl = moles of H+ ions
Moles of HCl = 0.6

3 0

3 years ago

Read 2 more answers

The solubility of potassium chloride is 34 g KCl

kenny6666 [7]

Answer: When 20 grams of potassium chlorate, KClO3, is dissolved in 100 grams of water at 80 ºC, the solution can be correctly described as:, unsaturated

At approximately what temperature does the solubility of sodium chloride, NaCl, match the solubility of potassium dichromate, K2Cr2O7?, 60 ºC

Explanation:

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3 years ago