A catalyst will

Which type of spectrum does the illustration A

Georgia [21]

Answer: Bright line

4 0

3 years ago

Read 2 more answers

DEFINE THESE WORDS FOR A TON OF POINTS!!!!!!!

PilotLPTM [1.2K]

Hi , these are the definitions
Chemistry; the science that deals with the composition and properties of substances and various elementary forms of matter.
aquatic system ; ecosystem in a body of water , communities and organisms that are dependent on each other.
depth ; the distance from the top to the bottom of something .
geography ; the study of the earth s physical features and the people ,plants , and animals.
light ; brightness from the sun or from a light.
medium ; between small and large in size.
period ; the name given to a horizontal row of the periodic table.
properties ; attributes of a substance.
refraction ; the change of direction of a ray of light , sound , heat ....
reflection ; reflection is when infrared waves bounce from a surface .
salinity ; a saline substance or a liquid that contains salt.
pressure ; measure of the force applied over an unit area .
photosynthesis ; the process used by plants , algae , and certain bacteria to harness energy from sunlight into chemical energy.
thermocline ; an abrupt temperature gradient in a body of water .
intertidal ; relating to the region between the hide tide mark and the low tide mark .
benthic ; relating to the bottom of a sea or a lake or to the organisms that live there .
pelagic ; relating to or living in the sea far from the shore.
epipelagic ; relating to or inhabiting the uppermost layer of the water column of the open ocean , into which enough sunlight enters for photosynthesis to take place.
mesopelagic ; relating to or inhabiting the layer of the water column in the open sea that lies between the epipelagic and bathypelagic layers at depths of about 200 to 1,000 meters.
bathypelagic ; relating to or inhabiting the layer of the water column of the open sea that lies between the mesopelagic and abyssopelagic layers at depths of about 1,000 to 4,000.
abyssopelagic ; refering to or occurring in the region of deep water above the floor of the ocean .
neritic ; region of water lying directly above the sub littoral zone of the sea bottom .
photic ; pertaining to the generation of light by organisms .
aphotic; zone of an ocean , lowest level at which photosynthesis can take place .
commensalism ; type of a relationship between a plant , an animal , fungus , etc.
competition ; the struggle among organisms .
freshwater systems ; subset of earth s aquatic ecosystems .
marine systems ; inside aquatic system , marine systems include oceans , seas ,etc.
mutual ism ; relation between species of organisms in which both benefit from the association.
organism ; a system with many parts that depends on each other and work together.
parasitism ; the behavior of a parasite .
predation; preying or plundering.
relationships ; the way in which two things are connected .
terrestrial systems ; an ecosystem only found on land forms.

4 0

3 years ago

he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c

Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer: The rate constant at 324°C is $61.29M^{-1}s^{-1}$

Explanation:

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

$\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_{244^oC}$ = equilibrium constant at 244°C = $6.7M^{-1}s^{-1}$

$K_{324^oC}$ = equilibrium constant at 324°C = ?

$E_a$ = Activation energy = 71.0 kJ/mol = 71000 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature = $244^oC=[273+244]K=517K$

$T_2$ = final temperature = $324^oC=[273+324]K=597K$

Putting values in above equation, we get:

$\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}$

Hence, the rate constant at 324°C is $61.29M^{-1}s^{-1}$

8 0

3 years ago

An unknown volume of gas has a pressure of 0.50 atm and temperature of 325 K. If the pressure is raised to 1.2 atm and the tempe

Grace [21]

You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!

4 0

3 years ago

How many moles do you have in 37.3 g of Co(CrO4)3

shutvik [7]

Answer:

0.0917 mol Co(CrO₄)₃

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis

Explanation:

Step 1: Define

37.3 g Co(CrO₄)₃

Step 2: Identify Conversions

Molar Mass of Co - 58.93 g/mol

Molar Mass of Cr - 52.00 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol

Step 3: Convert

$37.3 \ g \ Co(CrO_4)_3(\frac{1 \ mol \ Co(CrO_4)_3}{406.93 \ g \ Co(CrO_4)_3} )$ = 0.091662 mol Co(CrO₄)₃

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃

8 0

3 years ago