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faust18 [17]
2 years ago
13

Assume that a team of engineers runs a friction test on the car and track. The team finds that the car loses 210 joules of energ

y over each meter of track. How much energy does the roller coaster lose from friction as it travels from the top of the first hill to the top of the second hill
Physics
2 answers:
Reika [66]2 years ago
0 0

The rate of energy loss from friction is 210 joules/meter of track. Multiply by the length of the track (320 meters) to find the total energy lost:

210 J/m × 320 m = 67,200 J

The roller coaster car loses 67,200 joules of energy as heat between the tops of the two hills.

diamong [38]2 years ago
0 0

Answer:

The rate of energy loss from friction is 210 joules/meter of track. Multiply by the length of the track (320 meters) to find the total energy lost:

210 J/m × 320 m = 67,200 J

The roller coaster car loses 67,200 joules of energy as heat between the tops of the two hills.

Explanation:

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Estimate the mass of the Great Pyramid of Giza, in tons. You make may use of the following information: the Great Pyramid is in
postnew [5]

Answer:

6005803.83105 short tons

Explanation:

The definition of density is \rho = \frac{m}{V}, and the volume of a pyramid is (confusingly written on the proposal) V=\frac{1}{3} Ah, so we can write:

m=\rho V=\rho V \frac{1}{3} Ah=\rho V \frac{1}{3} s^2h

Where s is the side of the base, being s^2 the area of that square.

We will write everything in S.I., and the best way to convert units is using conversion factors, for example, since 1m=100cm, we know that \frac{1m}{100cm}=1, and we can use this factor to convert anything written in cm to anything written in m. Example:

500cm=500cm\frac{1m}{100cm}=5m

Here we just multiplied 500cm by something that is equal to 1 (as every conversion factor must), so <em>it's not doing anything but changing the units</em>.

We can use this tool like this:

2.1\frac{g}{cm^3}=2.1\frac{g}{cm^3}(\frac{1Kg}{1000g})(\frac{100cm}{1m})^3=2100Kg/m^3

Where we have used the fact that 1^3=1 (<u>we can elevate any conversion factor to any number and they still will be 1</u>) and where we have placed strategically what is the numerator and what in the denominator so the units we don't want cancel out and the units we want appear.

Substituting then our values:

m=\rho V \frac{1}{3} s^2h=(2100Kg/m^3)\frac{1}{3} (230.34m)^2(146.7m)=5448373586.96Kg

And now we will convert to short tons using two conversion factors at the same time:

m=5448373586.96\ Kg(\frac{1\ lb}{0.45359237\ Kg})(\frac{1\ short\ ton}{2000\ lb} )=6005803.83105\ short \ tons

Remember, their value is 1, and we place the units to cancel the ones we don't want and keep the ones we want, here Kg cancel out, and lb cancel out, leaving the short tones.

8 0
1 year ago
#1. How does a topographic map help an architect?
nignag [31]

Answer:

question #1 it is C

question #2 it is A

question #3 is i believe A

question #4 is D

question #5 is i believe is B

Explanation:

hope i helped and tell me if you need me to explain anything

6 0
1 year ago
Read 2 more answers
A spider accelerates from a standstill to 5m/s in 10s. What is its acceleration?
weqwewe [10]

Answer:

Acceleration = 0.5m/s²

Explanation:

Given the following data;

Final velocity = 5m/s

Time = 10 seconds

Since the spider started from rest, its initial velocity is equal to 0m/s

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In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

Substituting into the equation, we have;

a = \frac{5 - 0}{10}

a = \frac{5}{10}

Acceleration = 0.5m/s²

5 0
1 year ago
Whats the difference between work and power
Vika [28.1K]
The main relationship or difference between<span> the two is time. </span>Work<span> is the amount of energy necessary to move an object from one point to another. Imagine moving a table or seat from your living room to your dining room. On the other hand, </span>power<span> is the rate at which the energy is spent.</span>
8 0
1 year ago
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A hydraulic device is used to lift a block of 15 kg mass by 5 cm. (a) If the ratio of areas is A/a = 10, what force is required
goldfiish [28.3K]

To solve this problem it is necessary to use the concepts related to pressure. The pressure can be defined as

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Due to the continuity and pressure conservation relationship, the pressure must be preserved to support the weight (gravity) and to lift it (lift)

In this way,

P_g = P_l

\frac{F_g}{A} = \frac{F_l}{a}

That is equal to

\frac{F_g}{F_l}=\frac{A}{a}

We have a ratio of A/a = 10, then

\frac{F_g}{F_l} = 10

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Therefore the force required to do the lifting is 147.15N

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2 years ago
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