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faust18 [17]
3 years ago
13

Assume that a team of engineers runs a friction test on the car and track. The team finds that the car loses 210 joules of energ

y over each meter of track. How much energy does the roller coaster lose from friction as it travels from the top of the first hill to the top of the second hill
Physics
2 answers:
Reika [66]3 years ago
0 0

The rate of energy loss from friction is 210 joules/meter of track. Multiply by the length of the track (320 meters) to find the total energy lost:

210 J/m × 320 m = 67,200 J

The roller coaster car loses 67,200 joules of energy as heat between the tops of the two hills.

diamong [38]3 years ago
0 0

Answer:

The rate of energy loss from friction is 210 joules/meter of track. Multiply by the length of the track (320 meters) to find the total energy lost:

210 J/m × 320 m = 67,200 J

The roller coaster car loses 67,200 joules of energy as heat between the tops of the two hills.

Explanation:

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3 years ago
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As an object falls freely near the surface of the earth, its velocity?
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If it were possible for an object to fall freely near the surface of the Earth,

-- The direction of its velocity would always be "down"; that is, toward the center of the Earth.

-- The size of its velocity would continually increase, at the rate of 9.8 meters per second for every second it falls.

7 0
2 years ago
A boy 12.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the i
miss Akunina [59]

Answer:

Explanation:

Height covered = 12m

time to fall by 12 m

s = 1/2 gt²

12 = 1/2 g t²

t = 1.565 s

Horizontal distance of throw

= 8.5 x 1.565

= 13.3 m

This distance is to be covered by dog during the time ball falls ie 1.565 s

Speed of dog required = 13.3 / 1.565

= 8.5 m /s

b ) dog will catch the ball at a distance of 13.3 m .

4 0
3 years ago
The Olympic record for a marathon is 2.00 hour 9.00 minute 21.0 seconds if the average speed of the runner achieving this record
iren2701 [21]
(2.00 hours) x (3,600 seconds/hour)  =  7,200 seconds

(9.00 minutes) x (60 seconds/minute)  =  540 seconds

The record time = (7,200 + 540 + 21) = 7,761 seconds

Distance  =  (speed) x (time)

                 = (5.436 m/s) x (7,761 sec)  =<span>  42,188.8 meters
________________________________________________
</span>
The official length of the marathon run is  42,195 meters.
If we divide that by the record time in the question, we get

                       5.4368... m/s .

Rounded to the nearest thousandth, that's  5.437 m/s.

If the question had given the speed as  5.437  instead of  5.436 ,
then we would have calculated the distance to be 

            (5.437 m/s) x (7,761 sec)  =<span>  42,196.6 meters,

4.6 meters closer to the official distance than the answer we did get.
</span>
3 0
2 years ago
A basketball of mass 0.23kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a ve
Anna11 [10]

Answer:

8.1\:\mathrm{Ns}

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

\Delta p = m\Delta v, where m is the mass of the basketball and \Delta v is the change in velocity.

Since the basketball is changing direction, its total change in velocity is:

\Delta v = 20-(-15)=35\:\mathrm{m/s}.

Therefore, the basketball's change in momentum is:

\Delta p = m\Delta v = 0.23\cdot 35= 8.05=8.1\:\mathrm{kg\cdot m/s}.

Thus, the impulse on the basketball is \fbox{$8.1\:\mathrm{Ns}$} (two significant figures).

7 0
2 years ago
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