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faust18 [17]
3 years ago
13

Assume that a team of engineers runs a friction test on the car and track. The team finds that the car loses 210 joules of energ

y over each meter of track. How much energy does the roller coaster lose from friction as it travels from the top of the first hill to the top of the second hill
Physics
2 answers:
Reika [66]3 years ago
0 0

The rate of energy loss from friction is 210 joules/meter of track. Multiply by the length of the track (320 meters) to find the total energy lost:

210 J/m × 320 m = 67,200 J

The roller coaster car loses 67,200 joules of energy as heat between the tops of the two hills.

diamong [38]3 years ago
0 0

Answer:

The rate of energy loss from friction is 210 joules/meter of track. Multiply by the length of the track (320 meters) to find the total energy lost:

210 J/m × 320 m = 67,200 J

The roller coaster car loses 67,200 joules of energy as heat between the tops of the two hills.

Explanation:

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raketka [301]

Answer:

The car will make the turn perfectly

Explanation:

Given that the centripetal force= mv^2/r

M= mass of the car

v = speed of the car

r= radius

Hence;

F = 1000 × (14)^2/50

F= 3920 N

The frictional force = μmg

μ = coefficient of static friction

m= mass

g = acceleration due to gravity

Frictional force= 0.6 × 1000× 10

Frictional force = 6000 N

The car will not skid off the curve because the frictional force is greater than the centripetal force.

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3 years ago
What is the origin of the atomic emission spectrum of an element
lilavasa [31]

Answer:

The electronic transition of an electron back to a lower energy level generates an emission spectrum.

Explanation:

The atomic emission spectrum¹ of an element has its origin when an electronic transition² occurs. An electron in an atom or ion³will absorb energy coming from a source and pass to a higher energy level, the electron, upon returning to its base state will emit a photon⁴ or a series of photons.

Hence, that leads to the formation of an emission spectrum.

Remember that an electron has energy levels in an atom or ion, at which each energy level has a specific value.

The energy values will differ from one element to another. So, it can be concluded that each element has a unique pattern of emission lines.

Key terms:        

¹Spectrum: Decomposition of light in its characteristic colors.

²Electronic transition: When an electron passes from one energy level to another, either for the emission or absorption of a photon.

³Ion: An atom electrically charged due to the gain or loss of electrons.

⁴Photon: Elementary particle that constitutes light.

5 0
3 years ago
What is science?
vesna_86 [32]

Answer:

<h2>I don't know the answer but I have explanation </h2>

Explanation:

<h3>Science is further treated in a number of articles. For the history of Western and Eastern science, see science, history of. For the conceptualization of science and its interrelationships with culture, see science, philosophy of. For the basic aspects of the scientific approach, see physical science, principles of; and scientific method.Science can be divided into different branches based on the subject of study. The physical sciences study the inorganic world and comprise the fields of astronomy, physics, chemistry, and the Earth sciences. The biological sciences such as biology and medicine study the organic world of life and its processes. Social sciences like anthropology and economics study the social and cultural aspects of human behaviour.Science, any system of knowledge that is concerned with the physical world and its phenomena and that entails unbiased observations and systematic experimentation. In general, a science involves a pursuit of knowledge covering general truths or the operations of fundamental laws.</h3>

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3 years ago
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Two stones, one with twice the mass of the other, are thrown straight up and rise to the same height h. Compare their changes in
Lady bird [3.3K]
<h2>The gravitational potential energy is double for stone with twice the mass of other stone.</h2>

Explanation:

Let mass of stone 1 be m.

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