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Lyrx [107]
3 years ago
6

What is the distance in m between lines on a diffraction grating that produces a second-order maximum for 775-nm red light at an

angle of 62.5°?
Physics
1 answer:
8090 [49]3 years ago
4 0

Answer:

The distance is d =  1.747 *10^{-6} \ m  

Explanation:

From the question we are told that  

       The order of maximum diffraction is  m =  2

         The wavelength is   \lambda  =  775 nm  = 775 * 10^{-9}  \ m

         The angle is  \theta =  62.5^o

Generally the   condition for  constructive  interference for diffraction grating  is mathematically represented as

          dsin \theta  =  m *  \lambda

where  d is  the distance between the lines on a  diffraction grating

     So  

            d =  \frac{m *  \lambda  }{sin (\theta  )}

substituting values  

           d =  \frac{2  *  775 *1^{-9} }{sin ( 62.5  )}

          d =  1.747 *10^{-6} \ m

   

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What happens to the gravitational potential energy between two particles if the distance between them is halved? (a) It does not
mr_godi [17]

Answer:

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Explanation:

The gravitational force is the force of mutual attraction that two objects with mass experience.

The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:

F=G*\frac{m1*m2}{r^{2} }

where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives  the name of constant of gravitation.

If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:

F'=G*\frac{m1*m2}{(\frac{r}{2} )^{2} }

F'=G*\frac{m1*m2}{\frac{(r )^{2} }{2^{2} } }

F'=G*\frac{m1*m2}{\frac{(r )^{2} }{4} }

F'=4*G*\frac{m1*m2}{r^{2} }

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<u><em> The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).</em></u>

7 0
3 years ago
The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor
Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

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H = kx²/2mg

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mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0
3 years ago
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ladessa [460]

The other 4 kg of mass may have departed the scene
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7 0
3 years ago
Please help on this one?
Nonamiya [84]

30 or c because 60-30=30

3 0
4 years ago
What is an RC circuit? 
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Hope this helps!
8 0
3 years ago
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