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guapka [62]
3 years ago
12

The stage of the general adaptation syndrome when the body responds with changes that temporarily lower resistance is called ___

__.
Physics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

The correct answer to the following question will be "Alarm".

Explanation:

Hans Selye identified three replicated rates that the body needs to respond to the factors of stress, known as GAS (General Adaptation Syndrome).

There are various levels is which GAS consists, such as:

  • The alarm stage
  • The resistance stage
  • The exhaustion stage

Whenever the brain reacts with adjustments, the Alarm is considered momentarily lower resistance or this phase is the warning stage which generates an energy burst.

Therefore, an Alarm is the right answer.

Alisiya [41]3 years ago
4 0

Answer:

Alarm stage

Explanation:

Sympathetic branch is apart of person's autonomic nervous system (ANS) which governs the physiological changes.

At the alert response organize, a pain signal is sent to a piece of the mind called the nerve center. The nerve center empowers the arrival of hormones called glucocorticoids.

Glucocorticoids trigger the arrival of adrenaline and cortisol, which is a pressure hormone. The adrenaline gives an individual an increase in vitality. Their pulse increments and their circulatory strain rises. In the interim, glucose levels likewise go up.

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gizmo_the_mogwai [7]
The mechanical advantage of the screwdriver that is being described above is equal to 75N. This means that for every 30N that is applied on the screwdriver, this simple machine would in turn apply 75N of force to the lid of the can. 
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The clownfish is classified as an omnivore because it eats
vodka [1.7K]
Because it eats plants and animals. 
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Calculate the kinetic energy of an 86-kg scooter moving at 16 m/s
KIM [24]
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3 0
3 years ago
for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take th
mixas84 [53]

The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

<h3>Downward acceleration of the cylinder</h3>

The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;

Iα = Tr

where;

  • I is moment of inertia of the solid cylinder
  • α is angular acceleration of the cylinder
  • T is tension in the string
  • r is length of the string

α = Tr/I

\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}

where;

  • a is the downward acceleration of the solid cylinder
  • R is radius of the cylinder

Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

7 0
2 years ago
Two identical strings, of identical lengths of 2.00 m and linear mass density of μ=0.0065kg/m, are fixed on both ends. String A
kolezko [41]

Answer:

beat frequency = 13.87 Hz

Explanation:

given data

lengths l = 2.00 m

linear mass density μ = 0.0065 kg/m

String A is under a tension T1 = 120.00 N

String B is under a tension T2 = 130.00 N

n = 10 mode

to find out

beat frequency

solution

we know here that length L is

L = n × \frac{ \lambda }{2}      ........1

so  λ = \frac{2L}{10}  

and velocity is express as

V = \sqrt{\frac{T}{\mu } }    .................2

so

frequency for string A = f1 = \frac{V1}{\lambda}

f1 = \frac{\sqrt{\frac{T}{\mu } }}{\frac{2L}{10}}

f1 = \frac{10}{2L} \sqrt{\frac{T1}{\mu } }      

and

f2 = \frac{10}{2L} \sqrt{\frac{T2}{\mu } }

so

beat frequency is = f2 - f1

put here value

beat frequency = \frac{10}{2*2} \sqrt{\frac{130}{0.0065}}  - \frac{10}{2*2} \sqrt{\frac{120}{0.0065} }

beat frequency = 13.87 Hz

6 0
3 years ago
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