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3 years ago

PLz help with math in super confused. Will give u brainliest if u get it right.

Mathematics

1 answer:

asambeis [7]3 years ago

8 0

Answer:

The answer is A

Step-by-step explanation:

The answer is A because if you put all the ages of his patients along with their gender several are bound to overlap so it won't pass the vertical line test

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The table shows the profit and loss of the after -school snack stand write each profit as a positive number and each loss a nega

kiruha [24]

Answer:

Profit

7.50

4.50

Loss

-3.50

-6.00

Step-by-step explanation:

Here, we want to write each profit as a positive number and each loss as a negative number

thus, we have that;

Profit;

7.50

4.50

Loss;

-3.50

-6.00

7 0

3 years ago

What is the completely factored form of x3-64?

nataly862011 [7]

a^3 - b^3 = (a - b) (a^2 + ab + b^2)
so
x^3 - 4^3 = (x - 4)(x^2 + 4x + 16)

hope it helps

7 0

3 years ago

Read 2 more answers

Hi please help me with this i’ll give brainliest if you give a correct answer

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

a) PR=SU

b) PQ=TU

c) RQ=TS

5 0

3 years ago

Read 2 more answers

X + 4 1/3 = -2 5/6 find x

vladimir2022 [97]

Answer:

x = -7 1/6

Step-by-step explanation:

x + 4 1/3 = -2 5/6

x = -7 1/6

5 0

3 years ago

10. Determine the open interval(s) on which the function f(x) = 12x - x^3 is increasing.

Gre4nikov [31]

Answer:

$\large\boxed{x\in(-2,\ 2)}$

Step-by-step explanation:

$f(x)=12x-x^3$

Calculate the derivative of the function:

$f'(x)=\left(12x-x^3\right)'=(12x)'-\left(x^3\right)'=12-3x^2$

Calculate the zeros of the derivative:

$f'(x)=0\Rightarrow12-3x^2=0\qquad\text{add}\ 3x^2\ \text{to both sides}\\\\3x^2=12\qquad\text{divide both sides by 3}\\\\x^2=4\to x=\pm\sqrt4\\\\x=\pm2$

Let's check the derivative sign:

$f'(x)>0\iff12-3x^2>0\qquad\text{use the distributive property}\\\\-3(x^2-4)>0\\\\-3(x^2-2^2)>0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\-3(x-2)(x+2)>0\\^{\qquad x=2\qquad x=-2$

Sketch a parabola open down

(before the brackets there is the number -3 < 0)

Look at the picture.

Where the derivative is negative, the function decreases.

Where the derivative is positive, the function increases.

Therefore your answer is:

$x\in(-2,\ 2)$

3 0

4 years ago