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sesenic [268]
3 years ago
14

The speed of sound at room temperature (20 degrees Celsius) is 343 m/s. If the speed of sound in air increases about 0.60 m/s fo

r every 1 degrees Celsius increase, what is the temperature when the speed of sound is 353 m/s?
Physics
1 answer:
stepan [7]3 years ago
4 0

Answer:

36,67 degrees Celsius

Explanation:

The simplest way to approach this problem, given the information provided, is to simply start with the speed difference.

Goal: 353 m/s

Start: 343 m/s (at 20 degrees Celsius).

Difference: 10 m/s

Variation rate: 0.60 m/s/d (d = degree)

d = \frac{10 m/s}{0.60 m/s/d}  = 16,67 d

So, 16,67 degrees more than the starting point.

The temperature will then be 36.67 degrees Celsius, when the sound travels at the speed of 353 m/s.

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A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider
shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

d=v_x t

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

y(t) = h + v_y t - \frac{1}{2}gt^2

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s

So now we can find the magnitude of the initial velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s

4 0
3 years ago
A locomotive has a mass of 200,000kg. It is moving at 4.5m/s. Find its momentum .
anastassius [24]
Momentum (p) = mass × velocity

P= 200,000×4.5

P= 900,000 .... answer !!
4 0
3 years ago
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K.E = 1/2 mv²

    =  1/2 (70kg) (5.0ms)²

    =  1 ˣ ( 1750) / 2

    = 875 kgms²

     

3 0
3 years ago
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UkoKoshka [18]

Answer:

okay

Explanation:

(wish i could help but im just answering for points)

3 0
3 years ago
Which is not an example of a scalar?
Crank

Answer:

b) 2ft/s

Explanation:

A scalar has only magintude, not direction

6.2m, 3kg, and -100 o C are all scalars because they only have magnitude.

2ft/s is not a scalar because it has a direction.

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