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3 years ago

How much charge does a 9.0Vbattery transfer from the negative to the positive terminal while doing45Jof work?

Physics

1 answer:

sveticcg [70]3 years ago

3 0

Answer:

q = 5 coulombs.

Explanation:

Given :

Potential of battery , V = 9 V.

Work done in transferring charge from negative terminal to the positive terminal , W = 45 J.

We know, Work done by charge is product of its charge by its potential.

$W=q\times V$

Therefore, $q=\dfrac{W}{V}$

Putting values of W and V in above equation.

We get , $q=\dfrac{45}{9}=5\ coulombs.$

Hence, this is the required solution.

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