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serious [3.7K]
3 years ago
11

I need some help with this!

Physics
1 answer:
Sonja [21]3 years ago
5 0

Explanation:

ummm I believe it's frequency

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For an object that is speeding up at a constant rate in the positive direction,
Alla [95]

Answer:

B. A line angled upward

Explanation:

velocity is plotted along y- axis and time is plotted along x- axis so we get a line angled upward

7 0
3 years ago
A charge enters a uniform magnetic field oriented perpendicular to its path. The field deflects the particle into a circular arc
frozen [14]

Answer:

The new radius is three times the initial radius

Explanation:

The magnetic force is given by the equation

      F = q v x B

Where the blacks indicate vectors, q is the electric charge, v the velocity of the particle and B the magnetic field. The scalar magnitude of this force is

     F = q v B sin θ

Where θ is the angle between the velocity and the magnetic field.

As the force is perpendicular to the velocity, the particle describes a circular motion, using Newton's second law we can find the acceleration that is centripetal.

    F = ma

    a = v² / r

   

   q v B = mv² / r

  R = mv / qB

Let's calculate for the new speed (v₂ = 3v)

  R₂ = (m / qB) 3v

 R₂ = 3 R

 R₂ / R = 3

The new radius is three times the initial radius

7 0
3 years ago
If block D weighs 300 lb and block B weighs 275 lb determine the required weight of block C and the angle theta for equilibrium?
adoni [48]
Set up a free body diagram. 

<span>and by reason, Tcd = Tbd </span>

<span>Tbd y = 275 - 300*sinθ </span>
<span>Tcd y = Tc - 300*sin30 </span>

<span>Tbd x = 300*cosθ </span>
<span>Tcdx = 300 * cos30 </span>

<span>Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 </span>
<span>Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 </span>

<span>(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>etc.</span>
5 0
3 years ago
Which of these are not a natural resources: solar energy, wood, iron, diamonds.
Tcecarenko [31]
Diamonds and iron, as they can't be easily put back or recreated. Remember to make sure yourself.
Hope this helps :)
5 0
3 years ago
Calculate the velocity of the object in the graph during the following time interval 0-6 seconds. Also, during which time interv
cestrela7 [59]
Its accelarating from 1-10 i know that because the line is going up. i hope i helped
3 0
3 years ago
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