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3 years ago

I need some help with this!

Physics

1 answer:

Sonja [21]3 years ago

5 0

Explanation:

ummm I believe it's frequency

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5. During an anti-bullying club meeting after school, a student mentions that a new student has joined your class at school. The

Oksana_A [137]

Answer:

a. Constant gossiping, and talking negative about a student could cause them to feel very very ill about their beliefs, their familly, school, clothes, etc. this scenario will make the student feel alienated.

b. The club should advise the students that they should not participate in these talks, allow them into their groups, and should try to talk people out of those conversations.

c. The advice will keep several kids pull away from talking negatively about the kid, help stop the ill intended gossip, and hopefully make them feel better.

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3 years ago

A projectile is fired with a velocity of 45 m/s at an angle of 32°. What is the

Dennis_Churaev [7]

Answer:

Explanation:

To calculate adjacent of triangle use

$\cos(32) = \frac{a}{45}$

where 45 is the hypotenuse, and a is the adjacent side (horizontal component)

$45 \cos(32) = 38.16$

then round to 38.2

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3 years ago

The concept of photons applies to which regions of the electromagnetic spectrum?

Amanda [17]

Answer:

D. all regions of the spectrum

Explanation:

I did some research ; )

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3 years ago

. What is the energy of an object if the height is 20 m and the mass is 2kg?

navik [9.2K]

The kinetic energy of the object is 392 Joules.

6 0

3 years ago

6A certain load and set of slings create a 20-degree angle between the load and each sling leg. Using a spreader for the same li

Otrada [13]

Solution:

The angle between the sling and the load is $20^{\circ}$

So the tension in each sling can be calculated as

$Sin \theta = Mg => T = \frac{Mg}{2Sin\theta}$

$Sin \theta=> \frac{Mg}{2Sin 20^{\circ}}$

Where

M is the mass of the load

The Horizontal reaction on the sling will be inward.

After using the spreader, the new angle between sling and load is $60^{\circ}$ , the tension in the sling will be

$T= \frac{Mg}{2 Sin 60^{\circ}}$ = $\frac{Mg}{2 Sin 20^{\circ}}$

The tension will be same as before in the sling move away through the spreader at an angle more than 90 degree the horizontal force will act opposite and will be outward

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3 years ago