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Elan Coil [88]
3 years ago
10

Find the distance travelled when the initial angular velocity is 3rad/s the final angular velocity is 25rad/s and the time of mo

tion 10s
​
Physics
1 answer:
KIM [24]3 years ago
4 0

Answer:

Explanation:

If we ASSUME that angular acceleration is constant and the desired output is angular distance.

The average angular velocity is

ω = (3 + 25) / 2 = 14 rad/s

θ = ωt = 14(10) = 140 radians

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Answer:

C

Explanation:

A theory can be changed when new evidence is found. A law doesn't change because it is universally a fact. It doesn't need new evidence to support it.

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3 years ago
Suppose the acceleration of an elevator is 1/2 g upward, then what is the reading on the scale in the elevator.
Irina-Kira [14]

Answer:

c. 3/2 mg

Explanation:

Given that the acceleration of an elevator is 1/2 g upward.

The reading on the scale of the elevator is the net external force acting on the elevator.

Let the force F acting on the elevator as shown,

By using Newton's 2nd law, F_{net}=ma

where, F_{net} is the net force acting on the elevator.

m is the mass of the elevator,

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So, F_{net}=m\times \frac 1 2 g

F-mg=m\times \frac 1 2 g \\\\F=mg+ \frac 1 2 mg \\\\F= \frac 3 2 mg.

So, the reading on the scale in the elevator is \frac 3 2 mg.

Hence, option (c) is correct.

4 0
3 years ago
When two objects are near each other, how would increasing one object’s mass affect it?
worty [1.4K]

Answer:

b

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8 0
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A radioactive substance decays at an annual rate of 131313 percent. If the initial amount of the substance is 325325325 grams, w
anyanavicka [17]

Answer: f_{(t)}=325(0.87)^{t}

Explanation:

If we have an initial amount of a radioactive material or substance, which is 325g,  and we also are told this amount decays 13\% each year, this means each year 87\% of the substance remains:

100\%-13\%=87\%=0.87

<u />

<u>To understand it better:</u>

Year 1: 325(87\%)=325(0.87)

Year 2: 325(0.87)(0.87)=325(0.87)^{2}

Year 3: 325(0.87)(0.87)(0.87)=325(0.87)^{3}

and so on until year t:

Year t: 325(0.87)^{t}

Therefore, the function tha best describes this radiation decay situation is:

f_{(t)}=325(0.87)^{t}

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Mass of oxygen stays the same.

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