A) gases particles are far apart
Answer:
In physics, work is the amount of energy required to perform a given task (such as moving an object from one point to another). We start by defining the scalar product of two vectors, which is an integral part of the definition of work, and then turn to defining and using the concept of work to solve problems.
Answer:
v = a/√(2h/g) m/s
Explanation:
Lets say the distance away from the cliff is a.
then, a = v t
where v is velocity with which it was thrown and t is time taken to fall.
Using equations of motion, we can also say that
h=1/2gt^2
where h is the height of the cliff
Thus, t^2 = 2h/g and t = √(2h/g)
Thus, v = a/√(2h/g).
the vehicle was pushed off the cliff with the velocity , v = a/√(2h/g). m/s
Answer:
a) -31.36 m/s
b) 50.176 m
Explanation:
<h2>a) Velocity of the bag</h2>
This is a problem of motion in one direction (specifically vertical motion), and the equation that best fulfills this approach is:
(1)
Where:
is the final velocity of the supply bag
is the initial velocity of the supply bag (we know it is zero because we are told <u>it was "dropped", this means it goes to ground in free fall</u>)
is the acceleration due gravity (the negtive sign indicates the gravity is downwards, in the direction of the center of the Earth)
is the time
Knowing this, let's solve (1):
(2)
Hence:
Note the negative sign is because the direction of the bag is downwards as well.
<h2>b) Final height of the bag</h2>
In this case we will use the following equation:
(3)
Where:
is the distance the bag has fallen
remembering <u>the bag was dropped</u>
is the acceleration due gravity (downwards)
is the time
Then:
(3)
(4)
Finally:
