Question

Which is the equation in point-slope form of the line that contains points A and E?

Answer 1

Answer:

Point-slope form:  $y-4=\dfrac{3}{4}(x-4)$

Step-by-step explanation:

We are given some points on coordinate plane.

We need to find the equation of line in point slope form which passes through A and E

First we write the coordinate of point A and Point E

Point A: (-4,-2)

Point E:  (4,4)

Formula:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-4=\dfrac{-2-4}{-4-4}(x-4)$

$y-4=\dfrac{3}{4}(x-4)$

where,

$slope=\dfrac{3}{4}$

Hence, The slope point form of line is $y-4=\dfrac{3}{4}(x-4)$

Answer 2

Answer:

y+2 = 3/4(x+4)

or with the other point

y-4 = 3/4 (x-4)

Step-by-step explanation:

We can find the slope of the line since we have 2 points

A(-4,-2) and E(4,4)

m = (y2-y1)/(x2-x1)

    = (4--2)/(4--4)

   = (4+2)/(4+4)

   =6/8

   = 3/4

Then we can use point slope form

y-y1 = m(x-x1)

y--2 = 3/4 (x--4)

y+2 = 3/4(x+4)

or with the other point

y-4 = 3/4 (x-4)