In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction
The magnitude of static friction is
<em>f</em> = <em>mv</em> ²/<em>r</em>
(i.e. the net force acting on the car parallel to the road points toward the center of the curve)
while the net vertical force must be
∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0
because the car is otherwise in equilibrium. Then
==> <em>n</em> = <em>mg</em>
==> <em>f</em> = <em>µn</em> = <em>µmg</em> = <em>mv</em> ²/<em>r</em>
==> <em>µ</em> = <em>v</em> ²/(<em>rg</em>)
We have
<em>v</em> = 101 km/h ≈ 28.1 m/s
<em>r</em> = 110 m
<em>g</em> = 9.80 m/s²
so that
<em>µ</em> = (28.1 m/s)² / ((110 m) <em>g</em>) ≈ 0.730
Answer:
Acceleration = 3.67 m/s²
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
Given the following data;
Initial velocity, u = 5 m/s
Final velocity, v = 27
Time, t = 6
To find the acceleration;
Acceleration = (v - u)/t
Acceleration = (27 - 5)/6
Acceleration = 22/6
Acceleration = 3.67 m/s²
<span>Charging by friction occurs, Electrons are transferred when one object rubs against another.
Another example of this would be socks on carpet.
Hope this helps!</span>
Answer:
a) Frequency will increase
b)The f and r will vary similarly
Explanation:
from equation F=mω²r
ω=2πf
⇒Force, F is directly proportional to f and r
