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andrezito [222]
3 years ago
9

What type of wave is sound? light pressure electromagnetic gamma

Physics
2 answers:
erastovalidia [21]3 years ago
8 0

Answer:

The answer is pressure

Explanation:

Sound waves are produced as a result of vibrating bodies which causes the surrounding air to vibrate thereby producing disturbance which travels out in form of longitudinal waves

Sound waves can also be referred to as pressure waves because the compression and refraction that moves through sound waves are of varrying pressure.

The effect of the varrying pressure is responsible for the sound you hear.

I hope I answered your question.

JulijaS [17]3 years ago
3 0
Nu its pressure, just did this rn, 8th grade how the ear works physical science test
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At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l
Ksju [112]

Answer:

By convention a negative torque leads to clockwise rotation and a positive torque leads to counterclockwise rotation.

here weight of the child =21kgx9.8m/s2 = 205.8N

the torque exerted by the child Tc = - (1.8)(205.8) = -370.44N-m ,negative sign is inserted because this torque is clockwise and is therefore negative by convention.

torque exerted by adult Ta = 3(151) = 453N , counterclockwise torque.

net torque Tnet = -370.44+453 =82.56N , which is positive means counterclockwise rotation.

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Tnet = -370.44+377.5 = 7.06N-m , positive ,counterclockwise rotation.

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5 0
2 years ago
Write the equation of a function h(t) that represents the amount of heat in joules required to heat the bar to a temperature of
bearhunter [10]
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8 0
2 years ago
assuming that the air temperature is constant, what happens to a hot air balloon if it goes too far up in the atmosphere , where
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Hello!

The balloon explodes, because the pressure builds up inside and the air want to expand. Letter a)

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7 0
3 years ago
In a playground, there is a small merry-go-round of radius 1.20 m and mass 160 kg. Its radius of gyration is 91.0 cm. (Radius of
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Answer:

a) 145.6kgm^2

b) 158.4kg-m^2/s

c) 0.76rads/s

Explanation:

Complete qestion: a) the rotational inertia of the merry-go-round about its axis of rotation 

(b) the magnitude of the angular momentum of the child, while running, about the axis of rotation of the merry-go-round and

(c) the angular speed of the merry-go-round and child after the child has jumped on.

a) From I = MK^2

I = (160Kg)(0.91m)^2

I = 145.6kgm^2

b) The magnitude of the angular momentum is given by:

L= r × p The raduis and momentum are perpendicular.

L = r × mc

L = (1.20m)(44.0kg)(3.0m/s)

L = 158.4kg-m^2/s

c) The total moment of inertia comprises of the merry- go - round and the child. the angular speed is given by:

L = Iw

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w = 0.76rad/s

7 0
2 years ago
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anzhelika [568]
I think:
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