Question

Evaluate the expression when x = 4 and y = 5. Enter your answer in the box. 3x2 + 4y0 • x –1

Answer 1

3x^2+4y^0(x-1)
3(16)+4(1)(3)
48+12=60

Answer 2

Answer:

Step-by-step explanation:

Given: The given expression is:

$3x^2+4y^0(x-1)$

To find: The value of the expression at $x=4$ and $y=5$.

Solution: The given expression is:

$3x^2+4y^0(x-1)$

Substituting $x=4$ and $y=5$ in the above expression, we have

=$3(4)^2+4(5)^0(4-1)$

=$3(16)+4(1)(3)$

=$48+12$

=$60$

thus, the value of the given expression is $60$.