"Find the change in gravitational potential energy that the box undergoes as it rises to its final height."
1 answer:
Explanation:
Given that,
Mass of a box is 2.6 kg
(1) We need to find the work done on the box by this force as it is pushed up the 5.00-m ramp to a height of 3.00 m.
It means that the position of the object is 3 m i.e. h = 3 m
Work done = Fd
= mgh
So,
(2) Now the gravitational potential energy that the box undergoes as it rises to its final height is equal to the work done by the box. So,
Change in potential energy = 76.44 J
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Answer:
5.7141 m
Explanation:
Here the potential and kinetic energy will balance each other
This is the initial velocity of the system and the final velocity is 0
t = Time taken = 0.04 seconds
F = Force = 18000 N
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Equation of motion
From Newton's second law
Squarring both sides
The height from which the student fell is 5.7141 m
Answer:
a. 7.046 Nm²/C
b. 2.348 Nm²/C
Explanation:
Data given:
Base of equilateral triangle = 25.0 cm = 0.25 m
Strength of electric field = 260 N/C
In order to find the electric flux we first have to find out the area of triangle.
Area of triangle =
=
= 0.0271 m³
Lets find electric flux,
Electric Flux = E. A
= 260×0.0271
= 7.046 Nm²/C
Now we can find the electric flux through each of the three sides.
Electric flux through three sides =
= 2.348 N m²/C