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nadezda [96]
3 years ago
14

What is the resistance of resistor R3?

Physics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer: 2.0

Explanation: I KNOW !

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Describe each class of lever and explain to characteristics of each
Nataly [62]

-- Class I lever

The fulcrum is between the effort and the load.

The Mechanical Advantage can be anything, more or less than 1 .

Example:  a see-saw

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The load is between the fulcrum and the effort.

The Mechanical Advantage is always greater than 1 .

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-- Class III lever

The effort is between the fulcrum and the load.

The Mechanical Advantage is always less than 1 .

I can't think of an example right now.

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Individuals who suffer from a mental disorder are most likely to commit violent crimes. true or false
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Suppose you have three identical metal spheres, AA, BB, and CC. Initially sphere AA carries a charge qq and the others are uncha
Sedaia [141]

Complete Question

Suppose you have three identical metal spheres, A, B, and C. Initially sphere A carries a charge q and the others are uncharged. Sphere A is brought in contact with sphere B, and then the two are separated. Spheres CC and BB are then brought in contact and separated. Finally spheres AA and CC are brought in contact and then separated. What is the final charge on the sphere B, in terms of q?

a. 3/8q

b. 1/4q

c. 3/4q

d. q

e. 5/8q

f. 1/3q

g.1/2q

h. 0

Answer:

   The correct option is b

Explanation:

From the question we are told that

          The charge carried by A is  q C

           The charge carried by B is 0 C

            The charge carried by C is 0 C

When A and B are brought close and then separated the charge carried by  A and B is mathematically evaluated as

                 \frac{ 0 + q}{2} =   \frac{q}{2}

When C and B are brought close and then separated the charge carried by  C and B  is mathematically evaluated as    

                    \frac{0 + \frac{q}{2} }{2}  = \frac{q}{4}

When C and A are brought close and then separated the charge carried by  C and A  is mathematically evaluated as  

                       \frac{\frac{q}{4} +  \frac{q}{2} }{2}   = \frac{3q}{8}

Looking at these calculation we can see that the charge carried by B is

        \frac{q}{4} C

8 0
3 years ago
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