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diamong [38]
3 years ago
5

The worlds fastest humans can reach speeds of about 11 m/s in order to increase his gravitational potential energy by an amount

equal to his Kinetic energy at full speed how high with the sprinter need to climb
Physics
1 answer:
Amanda [17]3 years ago
4 0
 
What a delightful little problem !

-- When he is running on level ground, his kinetic energy is

             KE = (1/2) x (mass) x (speed)² .

-- When he climbs up from the ground, his potential energy is

             PE = (mass) x (gravity) x (height above the ground).

We're looking for the height that makes these quantities of energy equal,
figuring that when he runs, his speed is  11 m/s.

The first time I looked at this, I thought we would need to know the runner's
mass.  But it turns out that we don't.

       <u>PE = KE</u>

      (mass) x (gravity) x (height) = (1/2) (mass) (11 m/s)²

Divide each side by (mass) : 

       (gravity) x (Height)  =  (1/2) (11 m/s)²

Divide each side by gravity:

                      Height = (1/2) (121 m²/s²) / (9.8 m/s²)

                                =  <em>6.173 meters</em>

                         (about  20.3 feet !)


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Objects with masses of 235 kg and a 535 kg are separated by 0.330 m. (a) find the net gravitational force exerted by these objec
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A student, Daniela, is arguing that since a meteor is weightiess in space, if it crashes
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2 years ago
An open organ pipe of length 0.47328 m and another pipe closed at one end of length 0.702821 m are sounded together. What beat f
sineoko [7]

Answer:

fb = 240.35 Hz

Explanation:

In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.

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You replace in the equation (1):

f=\frac{343m/s}{2(0.47228m)}=362.36Hz      

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f'=\frac{v_s}{4L'}

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f'=\frac{343m/s}{4(0.702821m)}=122.00Hz

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The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz

7 0
3 years ago
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