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diamong [38]
3 years ago
5

The worlds fastest humans can reach speeds of about 11 m/s in order to increase his gravitational potential energy by an amount

equal to his Kinetic energy at full speed how high with the sprinter need to climb
Physics
1 answer:
Amanda [17]3 years ago
4 0
 
What a delightful little problem !

-- When he is running on level ground, his kinetic energy is

             KE = (1/2) x (mass) x (speed)² .

-- When he climbs up from the ground, his potential energy is

             PE = (mass) x (gravity) x (height above the ground).

We're looking for the height that makes these quantities of energy equal,
figuring that when he runs, his speed is  11 m/s.

The first time I looked at this, I thought we would need to know the runner's
mass.  But it turns out that we don't.

       <u>PE = KE</u>

      (mass) x (gravity) x (height) = (1/2) (mass) (11 m/s)²

Divide each side by (mass) : 

       (gravity) x (Height)  =  (1/2) (11 m/s)²

Divide each side by gravity:

                      Height = (1/2) (121 m²/s²) / (9.8 m/s²)

                                =  <em>6.173 meters</em>

                         (about  20.3 feet !)


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Answer:

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Explanation:

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What is tarzan's speed vf just before he reaches jane? express your answer in meters per second to two significant figures?
e-lub [12.9K]
Before swinging, T has only potential energy, (no speed)
Ui = mgh
Where h is the vertical displacement of T
From the laws of geometry,
cos45 = (L-h)/L
cos45 = 1-h/L
h/L = 1-cos45
h = L(1-cos45)

Therefore
Ui = mgL(1-cos45)

Proceeding the same way,
Twill raise to aheight of h' due to swing
h' = L(1-cos30)
The PE of T after swing is
Uf = mgh'
Uf = mgL(1-cos30)

Along with the PE , T has some kinetic energy results due to the moment.
Tf = 0.5*mv^2

According to the law of conservation of energy,
Ui = Uf+Tf
mgL(1-cos45) = mgL(1-cos30) + 0.5*mv^2
gL(co30-cos45) = 0.5*v^2
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<span>The speed f T after swing is 7.89 m/s</span>
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3 years ago
A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000
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The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

  • <em>Mass of the car, m = 1700 kg</em>
  • <em>Velocity of the car, v = 21 m/s</em>
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The final speed of the car is calculated as follows;

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Thus, the final speed of the car at the given conditions is 30.1 m/s.

Learn more about change in kinetic energy here: brainly.com/question/6480366

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