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hodyreva [135]
3 years ago
13

A whistle of frequency 592 Hz moves in a circle of radius 64.7 cm at an angular speed of 13.8 rad/s. What are (a) the lowest and

(b) the highest frequencies heard by a listener a long distance away, at rest with respect to the center of the circle?
Physics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

(a) lowest frequency=577 Hz

(b) highest frequency=608 Hz

Explanation:

Given data

f(whistle frequency)=592 Hz

ω(angular speed)=13.8 rad/s

r(radius)=64.7 cm=0.647 m

To find

(a) Lowest frequency

(b) highest frequency

Solution

From Doppler effect

f=f×{(v±vd)/(v±vs)}

Where

v is speed of sound

Vd is speed detector relative to the medium(vd=0)

Vs is the speed of the source

Since

v=rω

For (a) lowest frequency

f^{i}=f(\frac{v}{v+rw} )\\f^{i}=(592Hz)(\frac{343m/s}{343m/s+(0.647m)(13.8rad/s)} )\\f^{i}=577Hz

For (b) highest frequency

f^{i}=f(\frac{v}{v-rw} )\\f^{i}=(592Hz)(\frac{343m/s}{343m/s-(0.647m)(13.8rad/s)} )\\f^{i}=608Hz

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The position of an object in simple harmonic motion is defined by the function y = (0.50 m) sin (πt/2). Determine the maximum sp
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The maximum speed of the object under simple harmonic motion is 0.786 m/s.

The given parameters:

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<h3>Wave equation for simple harmonic motion;</h3>

y = A sin(ωt + Ф)

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The maximum speed of the object is calculated as follows;

V_{max} = A \omega\\\\V_{max} = 0.5 \times \frac{\pi}{2} = \frac{\pi}{4} \ m/s  = 0.786 \ m/s

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a pillow , a textbook and a paper airplane are dropped from the top of a tall building at the same time. consider what you have
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A textbook would hit the ground first


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3 years ago
Read 2 more answers
A 1100 kg sports car accelerates from 0m/s to 32m/s in 10 seconds. What is the average power of the engine?
timurjin [86]

Answer:

The average power of the engine of the sports car is 56.32 kW

Explanation:

Given;

mass of the sports car, m = 1100 kg

initial velocity of the sports car, u = 0 m/s

final velocity of the sports car, v = 32 m/s

time of motion, t = 10 s

The kinetic energy of the car is given by;

K.E = ¹/₂m(v² - u²)

K.E = ¹/₂mv²

K.E = ¹/₂ x 1100 x 32²

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The average power of the engine of the sports car is given by;

Pavg = Energy / time

Pavg = 563200 / 10

Pavg = 56320 W

Pavg = 56.32 kW

Therefore, the average power of the engine of the sports car is 56.32 kW

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3 years ago
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