All categories

3 years ago

What is the best estimate of 49% of 598

Mathematics

2 answers:

Maslowich3 years ago

4 0

49% of 598 = 598*49/100 = 293.02
<span> </span>

Alborosie3 years ago

3 0

49% of 598: 598x0.49=293.02

You might be interested in

In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track

Aloiza [94]

Answer:

Approximately $0.31\; \rm m$ , assuming that $g = 9.81\; \rm N \cdot kg^{-1}$ .

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

$\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned}$ .

Weight of the slide:

$\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}$ .

Normal force between the sled and the slope:

$\begin{aligned}F_{\rm N} &= W\cdot \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}$ .

Calculate the kinetic friction between the sled and the slope:

$\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}$ .

Assume that the sled and its passenger has reached a height of $h$ meters relative to the base of the slope.

Gain in gravitational potential energy:

$\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}$ .

Distance travelled along the slope:

$\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}$ .

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

$\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}$ .

In other words, the sled and its passenger would have lost (approximately) $((137 + 68.1)\, h)\; {\rm J}$ of energy when it is at a height of $h\; {\rm m}$ .

The initial amount of energy that the sled and its passenger possessed was $\text{KE} = 63\; {\rm J}$ . All that much energy would have been converted when the sled is at its maximum height. Therefore, when $h\; {\rm m}$ is the maximum height of the sled, the following equation would hold.

$((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}$ .

Solve for $h$ :

$(137 + 68.1)\, h = 63$ .

$\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}$ .

Therefore, the maximum height that this sled would reach would be approximately $0.31\; \rm m$ .

7 0

2 years ago

Ben went to the hardware store and bought 7 pieces of rope of equal length. The total length of the ropes was 56 meters. How lon

Harman [31]

Answer:

8 meters

Step-by-step explanation:

56 / 7 = 8

6 0

3 years ago

Can someone help??.?.

Butoxors [25]

Answer: 8/100

Step-by-step explanation: I converted 5/10 in 50/100 and subtracted 50 from 58 and got 8 so the answer is 8/100.

8 0

2 years ago

Read 2 more answers

a company manufactures rectangular cardboard boxes. each box is 20 inches long and 15 inches wide. the heights of the boxes rang

Bogdan [553]

The range of possible values for the volume of the boxes would be 1200 - 1800 cubic inches

The dimensions of the rectangular cardboard boxes are given as

Case I

Length = 20 inches

breadth = 15 inches

Height = 4 inches

Volume of the rectangular cardboard box in case I = Length x breadth x breadth

= 20 x 15 x 4

= 1200 cubic inches

Similarly,

Case II

Length = 20 inches

breadth = 15 inches

Height = 6 inches

Volume of the rectangular cardboard box in case I = Length x breadth x breadth

= 20 x 15 x 6

= 1800 cubic inches

To learn more about volume, here

brainly.com/question/1578538

#SPJ4

4 0

1 year ago

Hellppp 70 pointsss

dimulka [17.4K]

y=a.(X-x1)(X-x2)

x1 and x2 are x-intercepts

x1=-3

x2=1

other points: (-1,8) and (0,5)

y=a.(x+3).(x-1)

a=-2

f(x)= -2.(x+3)(x-1)

7 0

2 years ago