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3 years ago

Which of the following supplies the heat for the hot reservoir in a car's engine?

2 answers:

8 0

Out of the choices given, igniting the gas-air mixture supplies the heat for the hot reservoir in a car's engine. The correct answer is C.

Aleks [24]3 years ago

8 0

Answer: The correct answer is "igniting the gas-air mixture".

Explanation:

Internal combustion engine is a heat engine. Here, the combustion of the fuel occurs with air.

Internal combustion is fed with fossil fuel like petroleum, natural gas product such as gasoline.

The expansion of high temperature and high pressure gases are produced by the combustion. These gases apply the direct force to some component of engine.

Therefore, the heat is supplied for the hot reservoir in car's engine by igniting the gas-air mixture.

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1. A 2.10 m rope attaches a tire to an overhanging tree limb. A girl swinging on the

musickatia [10]

Answer:

29.6 kg

Explanation:

Centripetal force = mass × centripetal acceleration

F = m v² / r

88.0 N = m (2.50 m/s)² / 2.10 m

m = 29.6 kg

3 0

3 years ago

The pressure difference, , across a partial blockage in an artery (called a stenosis) is approximated by the equation where is t

Strike441 [17]

The question is incomplete. The complete question is :

The pressure difference, Δp, ac $K_u$ ross a partial blockage in an artery (called a stenosis) is approximated by the equation :

$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$

Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the artery diameter, $A_0$ the area of the unobstructed artery, and A1 the area of the stenosis. Determine the dimensions of the constants $K_v$ and $K_u$ . Would this equation be valid in any system of units?

Solution :

From the dimension homogeneity, we require :

$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$

Here, x means dimension of x. i.e.

$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$

$=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$

So, $[K_u]=[K_v]=[1 ]=$ dimensionless

So, $K_u$ and $K_v$ are dimensionless constants.

This equation will be working in any system of units. The constants $K_u$ and $K_v$ will be different for different system of units.

5 0

3 years ago

A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50 m/s. The goal is to have the cannonball t

Rudiy27

Answer: It will fall short of its goal.

Explanation: I took the quiz.

7 0

3 years ago

So we were working on some pulley problems but this one has kinda left me scratching my head, please help! My question is for pa

USPshnik [31]

Explanation:

Sum of forces on B in the -y direction:

∑F = ma

mBg − T = mBa

Sum of forces on A in the +x direction:

∑F = ma

T = mAa

Substitute:

mBg − mAa = mBa

mBg − mBa = mAa

mA = mB (g − a) / a

Plug in values:

mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))

mA = 495 kg

The answer key seems to have a mistake. It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.

8 0

3 years ago

If a total force exerted by water in a container with a bottom area of 3 square meters is 900 newtons, what's the water pressure

anyanavicka [17]

<h3>Answer:</h3>

p=300 Pa

<h3>Explanation:</h3>

_______________

S=3 m²

F=900 N

_______________

p - ?

_______________

p=F/S=900 N / 3 m² = 300 Pa

6 0

1 year ago