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3 years ago

Which of the following supplies the heat for the hot reservoir in a car's engine?

2 answers:

8 0

Out of the choices given, igniting the gas-air mixture supplies the heat for the hot reservoir in a car's engine. The correct answer is C.

Aleks [24]3 years ago

8 0

Answer: The correct answer is "igniting the gas-air mixture".

Explanation:

Internal combustion engine is a heat engine. Here, the combustion of the fuel occurs with air.

Internal combustion is fed with fossil fuel like petroleum, natural gas product such as gasoline.

The expansion of high temperature and high pressure gases are produced by the combustion. These gases apply the direct force to some component of engine.

Therefore, the heat is supplied for the hot reservoir in car's engine by igniting the gas-air mixture.

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Two blocks are connected by a string over a pulley. The hanging block has a mass of 8-kg and the one on the plane has a mass of

jeka94

Answer:

Let f be force of friction on the blocks kept on inclined plane. T be tension in the string

For motion of block on the inclined plane in upward direction

T - m₁gsin40 - f = m₁a

f = μ m₁gcos40

For motion of hanging block on in downward direction

m₂g - T = m₂ a

Adding to cancel T

m₂g - - m₁gsin40 - μ m₁gcos40 = a ( m₁+m₂ )

a = g (m₂ - - m₁sin40 - μ m₁cos40) / ( m₁+m₂ )

Putting the values

a = 9.8 ( 4.75 - 2.12-1.045) / 7.6

2.04 m s⁻²

M₂ will go down and M₁ will go up with acceleration .

Explanation:

7 0

3 years ago

A shovel pushes on dirt and the dirt pushes back on the shovel. The dirt pushing back is

Leno4ka [110]

The dirt pushing back is the 'resistance' force. It RESISTS your attempts to shovel it.

6 0

3 years ago

The water behind Grand Coulee Dam is 1000 m wide and 200 m deep. Find the hydrostatic force on the back of the dam. (Hint: the t

Vika [28.1K]

Answer:

The hydro static force on the back of the dam is $1.96\times10^{11}\ N$

Explanation:

Given that,

Width b= 1000 m

Depth d= 200 m

We need to calculate the average pressure

Using formula of average pressure

$P_{avg}=\rho\times g\times d_{avg}$

Put the value into the formula

$P_{avg}=1000\times9.8\times100$

$P_{avg}=980000\ Pa$

We need to calculate the hydro static force on the back of the dam

Using formula of force

$F = P_{avg}\times A$

Put the value into the formula

$F = 980000\times1000\times200$

$F=1.96\times10^{11}\ N$

Hence, The hydro static force on the back of the dam is $1.96\times10^{11}\ N$

7 0

3 years ago

What is the difference in intensity for two sounds that are 40 dB apart?

Galina-37 [17]

the difference of 10 dB is considered as having 10 times the intensity, so difference of 40 dB means :

=》10 × 10 × 10 × 10

=》10000 times

so the the intensity of one sound is 10000 times the other one.

4 0

3 years ago

Read 2 more answers

A motorcyclist is trying to leap across a canyon by driving horizontally off the higher side of the canyon at a speed of 78.0 m/

CaHeK987 [17]

Answer:

v = (78.0 i ^ - 70.27 j ^) m/s, v = 105 m / s , θ = 318º

Explanation:

We have a projectile launch problem, let's start by calculating the time it takes to get through the canyon

y = $v_{oy}$ t - ½ gt2

As the motorcyclist comes out horizontally, the speed he has is the horizontal speed (vox) and the initial vertical speed is zero (I go = 0)

y = 0 - ½ g t2

t = √ 2y / g

t = √ (2 252 /9.8)

t = 7.17 s

Let's calculate the vertical speed for this time

$v_{y}$ = $v_{oy}$ - gt

$v_{y}$ = 0 - gt

$v_{oy}$ = - 9.8 7.17

$v_{oy}$ = - 70.27 m / s

We can give the result in two ways

First:

v = (78.0 i ^ - 70.27 j ^) m / s

Second:

using the Pythagorean theorem and trigonometry

v² = vₓ² + $v_{oy}$ ²

v = √ [(78.0)² + (-70.42)²] = √ (11042.98)

v = 105 m / s

tan θ₁ = $v_{y}$ y / vₓ

tan θ₁ = -70.42 / 78.0

θ₁ = 42º

If we measure this angle from the positive direction of the x-axis counterclockwise

θ = 360 - θ₁

θ = 360 - 42

θ = 318º

8 0

3 years ago