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7nadin3 [17]
3 years ago
15

Heat can be transferred through conduction, convection, and radiation. What is necessary in order for heat to be transferred by

conduction?
A.
Heat must be transferred through space.
B.
Heat must be transferred in the form of currents.
C.
The substances must be liquids or gases.
D.
The objects must be in direct contact with one another.
Physics
2 answers:
Pie3 years ago
7 0
Conduction is a mode of heat transfer where thermal energy flows between bodies that are in direct contact. Thus, the correct answer would be D.

A is incorrect here: heat flow via conduction involves high-energy particles (such as atoms or molecules) having their energy transferred to neighboring particles by contact or collision. If “space” refers to a region that contains only gas (the everyday understanding of “space”), then heat transfer by conduction would be extremely inefficient since gas molecules are so far apart. If “space” refers to a vacuum, then conduction cannot occur at all (radiation is the only mode of heat transfer through a vacuum). In either case, not only does conduction not necessitate space, but space impedes heat transfer by conduction.

B is incorrect because conduction operates via the movement of energy itself and not of matter (although, as we established above, the presence of matter is necessary for conduction). Conductive heat transfer can occur within a body itself (a metal bar that is heated on one end will eventually become hot on the other end). So, apart from being definitionally incorrect, conductive heat transfer doesn’t require currents at all. This mode of heat transfer occurs in convection.

C is manifestly incorrect: conductive heat transfer can occur between or within solids, so it can’t possibly be necessary that the “substances . . . Be liquids or gases.
jeka943 years ago
3 0

it would be..... C

sorry if I am wrong I tryed to think, At least I try!

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puteri [66]
A an objects weight hope this helps! :D 
3 0
3 years ago
A large meteoroid enters the Earth's atmosphere at a speed of 20.0 km/s and is not significantly slowed before entering the ocea
Shalnov [3]

The shock wave from the meteoroid in the lower atmosphere has a Mach angle of 0.948°.

(a) The meteoroid's speed v_s=20 \mathrm{~km} / \mathrm{s}

$=20 \times 10^3 \mathrm{~m} / \mathrm{s}$

Air sound wave speed &v=331 \mathrm{~m} / \mathrm{s} \\

Speed of the shock wave in Mach &\qquad \theta=\sin ^{-1}\left(\frac{v}{v_s}\right)

                                                            $$\begin{aligned}&=\sin ^{-1}\left(\frac{331 \mathrm{~m} / \mathrm{s}}{20 \times 10^3 \mathrm{~m} / \mathrm{s}}\right) \\&=0.948^{\circ}\end{aligned}$$

Hence, 0.948° is the Mach angle of the shock wave from the meteoroid in the lower atmosphere.

<h3>What is the speed of the meteoroid?</h3>

A meteoroid's speed can be loosely broken down into three categories: slow, medium, and fast.

  • Slow meteors move around the sun at a leisurely pace of about 32 kilometers per second (20 miles per second).
  • Medium-speed meteors travel around the sun at approximately 50 kilometers per second (30 miles per second),
  • while fast meteors zoom past at over 120 kilometers per second (75 miles per second)!

To learn more about meteoroid, visit:

brainly.com/question/1939309

#SPJ4

5 0
1 year ago
When developing a question for a scientific inquiry, the question will ideally
Lisa [10]
When developing a question for a scientific inquiry, the question will ideally :

- be measurable
- Will have various variables that could be used for further testing
- not just simply ask why

hope this helps
7 0
3 years ago
Read 2 more answers
When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic
alexandr1967 [171]

Coefficient of volume expansion is 8.1 ×10⁻⁴ C⁻¹.

<u>Explanation:</u>

The volume expansion of a liquid is given by ΔV,

ΔV = α V₀ ΔT

ΔT = change in temperature  = 48.5° C

α =  coefficient of volume expansion =?

V₀ = initial volume = 2.35 m³

We need to find α , by plugin the given values in the equation and by rearranging the equation as,

\alpha=\frac{\Delta \mathrm{V}}{\mathrm{V}_{0} \Delta \mathrm{T}}=\frac{0.0920}{2.35 \times 48.5}=0.00081

  = 8.1 ×10⁻⁴ C⁻¹.

5 0
3 years ago
I REALLY NEED HELP ON THIS PLEASE HELP ME
Lapatulllka [165]

Answer:

I have no clue lol

Explanation:

8 0
2 years ago
Read 2 more answers
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