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7nadin3 [17]
3 years ago
15

Heat can be transferred through conduction, convection, and radiation. What is necessary in order for heat to be transferred by

conduction?
A.
Heat must be transferred through space.
B.
Heat must be transferred in the form of currents.
C.
The substances must be liquids or gases.
D.
The objects must be in direct contact with one another.
Physics
2 answers:
Pie3 years ago
7 0
Conduction is a mode of heat transfer where thermal energy flows between bodies that are in direct contact. Thus, the correct answer would be D.

A is incorrect here: heat flow via conduction involves high-energy particles (such as atoms or molecules) having their energy transferred to neighboring particles by contact or collision. If “space” refers to a region that contains only gas (the everyday understanding of “space”), then heat transfer by conduction would be extremely inefficient since gas molecules are so far apart. If “space” refers to a vacuum, then conduction cannot occur at all (radiation is the only mode of heat transfer through a vacuum). In either case, not only does conduction not necessitate space, but space impedes heat transfer by conduction.

B is incorrect because conduction operates via the movement of energy itself and not of matter (although, as we established above, the presence of matter is necessary for conduction). Conductive heat transfer can occur within a body itself (a metal bar that is heated on one end will eventually become hot on the other end). So, apart from being definitionally incorrect, conductive heat transfer doesn’t require currents at all. This mode of heat transfer occurs in convection.

C is manifestly incorrect: conductive heat transfer can occur between or within solids, so it can’t possibly be necessary that the “substances . . . Be liquids or gases.
jeka943 years ago
3 0

it would be..... C

sorry if I am wrong I tryed to think, At least I try!

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Explanation:

Use Pythagorean theorem:

r² = x² + y²

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r = 7.48 m

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2 years ago
What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T ma
Sindrei [870]

Answer:

E = 1.50 × 10^{8} V/m

Explanation:

given data

B = 0.50 T

solution

we know that energy density by the magnetic field is express as

\mu _b = \frac{B}{2\mu _o}   ...............1

and

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\mu _e = \frac{\epsilon _o E^2}{2}     ...............2

and here \mu _b = \mu _ e

so that

E = \frac{B}{\sqrt{\mu _o \times \epsilon _o}}      ...................3

put here value and we get

E = \frac{0.50}{\sqrt{4\pi \times 10^{-7} \times 8.852 \times 10^{-12}}}  

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6 0
3 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
svetoff [14.1K]

Answer:

The equation of motion is x(t)=-\frac{1}{3} cos4\sqrt{6t}

Explanation:

Lets calculate

The weight attached to the spring is 24 pounds

Acceleration due to gravity is 32ft/s^2

Assume x , is spring stretched length is ,4 inches

Converting the length inches into feet x=\frac{4}{12} =\frac{1}{3}feet

The weight (W=mg) is balanced by restoring force ks at equilibrium position

mg=kx

W=kx ⇒ k=\frac{W}{x}

The spring constant , k=\frac{24}{1/3}

                            = 72

If the mass is displaced from its equilibrium position by an amount x, then the differential equation is

    m\frac{d^2x}{dt} +kx=0

    \frac{3}{4} \frac{d^2x}{dt} +72x=0

  \frac{d^2x}{dt} +96x=0

Auxiliary equation is, m^2+96=0

                                 m=\sqrt{-96}

                               =\frac{+}{} i4\sqrt{6}

Thus , the solution is x(t)=c_1cos4\sqrt{6t}+c_2sin4\sqrt{6t}

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The mass is released from the rest x'(0) = 0

                    =-4\sqrt{6c_1} sin4\sqrt{6(0)}+c_2 4\sqrt{6} cos4\sqrt{6(0)} =0

                                                    c_2 4\sqrt{6} =0

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Therefore , x(t)=c_1 cos 4\sqrt{6t}

Since , the mass is released from the rest from 4 inches

                    x(0)= -4 inches

c_1 cos 4\sqrt{6(0)} =-\frac{4}{12} feet

   c_1=-\frac{1}{3} feet

Therefore , the equation of motion is  -\frac{1}{3} cos4\sqrt{6t}

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