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Kobotan [32]
3 years ago
9

How do helmets protect your head? a. By creating a large area to spread out the pressure of a blow to your head. b. By focusing

the pressure of a blow into a small area. c. By creating a vacuum that protects your head. d. By creating a pressure gradient that traps energy away from your skull.
Physics
2 answers:
vagabundo [1.1K]3 years ago
8 0
I think its c.by creating a pressure gradient that traps energy away from your skull.

Andru [333]3 years ago
5 0
Your answer is A.

I hope this helps
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A painter sits on a scaffold that is connected to a rope passing over a pulley. The other end of the rope rests in the hands of
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Solution :

a). From Newtons second law,

F = ma

The total tension force is 2T.

∴ 2T - (m + M)g = (m+ M)a

Then

$a=\frac{2T-(m+M)g}{m+M}$

$a=\frac{2\times 600-(52+63)9.8}{52+63}$

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b). From the person,

   F = ma

 T - Mg + N = Ma

or N = Ma + Mg - T

        = (63 x 9.8) + (52 x 9.8) - 600

        = 617.4 + 509.6 - 600

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Which of the following properties of materials does NOT affect resistance?
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B thickness

Explanation:

thickness

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What is the speed of a helicopter that traveled 1500 miles in 7 hours?
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How does a real image differ from a virtual image?
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Two particles with masses m and 3m are moving toward each other along the x axis with the same initial speeds Vi. Particle m is
nignag [31]

Answer:

v1 = \sqrt{(2)}Vi

v2 = \sqrt{(2/3)}Vi

ANGLE is 35.3 degree celcius

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Given data:

mass m and 3m

initial speed Vi

particle with mass m is moving toward left while particle with mass 3m is moving toward right

By using conservation of momentum :

mVi + 3m(-Vi) = mv1 +3mv2

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conservation of energy :

m(Vi^2) + 3m(-Vi^2) = mv1^2 + 3mv2^2

4mVi^2 = m(v1^2+3v2^2)

4Vi^2 = v1^2+3v2^2

After collision, particle with mass m moves at right angles, thus by considering conservation of momentum in x & y direction,

x direction : -2mVi = 3m.v2i

-2Vi = 3v2i

y direction : 0 = m(v1)j+3m(v2)j

-v1j = 3v2j

subsitute these value in energy conservation

v1 = \sqrt{(2)}Vi

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3 years ago
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