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ivann1987 [24]
4 years ago
10

The model below shows a carbide ion. 8 light grey and 6 dark grey balls sit at the center with 2 concentric black rings around t

hem. The inner ring has 2 medium grey balls on it, and the outer ring has 8 medium grey balls on it. At bottom, a dark grey ball = +1, a light grey ball = 0, a medium grey ball = negative 1. What could be done to change this carbide ion to a neutral carbon atom?
Physics
1 answer:
azamat4 years ago
6 0

Answer:

This carbide ion change into a neutral carbon atom.

Explanation:

Given that,

Light grey balls = 8

dark grey balls = 6

medium grey balls = 2

Charge on dark grey ball = +1

Charge on light grey ball = 0

Charge on medium grey ball = -1

We need to change this carbide ion to a neutral carbon atom

Using given data

A dark grey ball has one positive charge. It means, it is a proton.

A light grey ball has has zero charge. It means, it is a neutron.

A medium grey ball has one negative charge.It means, it is a electron.

We know that,

The number of proton and number of electron is equal in a neutral atom.

So, No charge is present on the given model of atom.

Therefore, we can say that the atom is neutral.

We know that,

The sum of total number of protons presents in an atom it is called atomic number.

So, The total number of protons is 8, the total number of electrons is 8 and the total number of neutrons is 9 in given atom.

Hence, This carbide ion change into a neutral carbon atom.

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navik [9.2K]

the upside down image means an inverted image and for an inverted image, magnification is negative

so the answer is -m

4 0
4 years ago
You and your roommate are moving to a city360 mi away. Your roommate drives a rental truck at a constant 50 mi/h , and you drive
AnnyKZ [126]

Answer:

42 minutes

Explanation:

First, let us find out the time required by the roommate, who is driving the truck, to reach the city.

We know that,

time=\frac{distance}{speed} =\frac{360}{50} hrs=7.2hrs

Now, you are planning to rest a bit after traveling for an hour. So,

distance covered in that 1 hour = 60mi/h\times1h=60 miles

time required by you to cover the total distance = \frac{360mi}{60mi/h} =6hours

If you wish reach at the destination half an hour (0.5 h) before your roommate, you can expend a total of 7.2-0.5=6.7hours throughout your journey.

Hence, you can rest for  6.7-6=0.7hours=(0.7\times60)minutes=42minutes

3 0
3 years ago
If i fail choir do i fail 7th grade
Strike441 [17]

Answer:

no ....................

7 0
3 years ago
Read 2 more answers
A total charge of –6.50 µC is uniformly distributed within a sphere that has a radius of 0.150 m. What is the magnitude and dire
Marrrta [24]

Answer:

A) 2.89 × 105 N/C, radially inward

Explanation:

The magnitude of the electric field generated by a charged sphere is given by the following formula:

E=k\frac{Q}{r^2}  ( 1 )

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

Q: charge of the sphere = -6.50*10^-6 C

r: distance from the center of the sphere to the point in which E is calculated

r = 0.150m + 0.300m = 0.450 m

You replace the values of Q and r in the equation (1):

E=(8.98*10^9Nm^2/C^2)\frac{6.50*10^{-6}C}{(0.450m)^2}=288246.91\frac{N}{C}\\\\E\approx2.89*10^5\frac{N}{C}

The electric field points radially inward because the charge is negative.

hence, the answer is:

A) 2.89 × 105 N/C, radially inward

7 0
4 years ago
Unpolarized light is incident upon two polarization filters that do not have their transmission axes aligned. If 21% of the ligh
Debora [2.8K]

Answer:

49.6°

Explanation:

I_0 = Unpolarized light

I_2 = Light after passing though second filter = 0.21I_0

Polarized light passing through first filter

I_1=\frac{I_0}{2}

Polarized light passing through second filter

I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.21I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.21I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.21\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.42}\\\Rightarrow \theta=49.6^{\circ}

The angle between the two filters is 49.6°

5 0
4 years ago
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