Answer:
64 people/m^2
Step-by-step explanation:
The population density can be found by diving the number of people by the amount of area
I assume that the answer should be in metre squares or the area should be 1.95 million km^2
124000000/(1.95*1000000)
=63.5897...
=64 people/m^2
Answer:
The cost per print expressed as a slope is 7.125
Step-by-step explanation:
To calculate the cost per print, let’s envision that we have a graphical representation of cost of posters against the number of posters
We have the cost on the y-axis and the number of posters on the x axis
With the information given in the question, we shall be having two data points
Point 1 = (32,126)
point 2 = (48,240)
Now to find the slope of the line which is cost per print, we make use of both points in the slope equation.
Mathematically, slope m will be
m = y2-y1/x2-x1
Thus, we have;
m = (240-126)/(48-32)
m = 114/16
m = 7.125
The cost per print expressed as a slope is 7.125
A little tip: you should put the question in next time :)!
<h2>
Translating Words into Problems</h2>
We can translate a word equation into a mathematical equation by translating key words into operations.
- <em>difference</em> = subtract
- <em>is</em> = equals
<h2>Addinng Fractions</h2>
Whenever we need to add one fraction to another, we must find a common denominator, change both the fractions for their denominators to be the same, and then add the numerators. Finally, we reduce the fraction.
<h2>Solving the Question</h2>
We're given:
- The difference of n and
is 
.
Translate the given information into an equation:
⇒ 
Solve for <em>n</em>:
⇒ 
<h2>Answer</h2>
Answer:
x=((log(81))/(log(3))+2)/3
Step-by-step explanation:
so what you want to do is get 3x-2 out of the exponent
you can do that by using log
so apply log to both sides and you get
log(81)=(3x-2)log(3)
the 3x-2 is moved in front of the log due to a log rule
then (log(81))/(log(3))=3x-2
(log(81))/(log(3))+2=3x
((log(81))/(log(3))+2)/3=x
then use a calculator to find the exact value
hope this helps im sorry my explanation is a bit confusing, ask any questions you have
