Answer:
break power = 6.031 kW
indicated power = 6.859 kW
total frictional power = 0.827 kW
total friction imep = 111.26 kpa
Explanation:
given data
Vd = 0.496 L
revolving = 1800 rpm
brake torque T = 32 Nm
gross imep = 933 kPa
net imep = 922 kP
solution
first we get here break power that is
break power = ............1
put here value we get
break power =
break power = 6.031 kW
and
indicated power will be
indicated power = ..........2
put here value
indicated power =
indicated power = 6.859 kW
and
total frictional power will be
total frictional power = indicated power - break power .......3
total frictional power = 6.859 - 6.031
total frictional power = 0.827 kW
and
total friction imep will be
total friction imep = ..........4
put here value
total friction imep =
total friction imep = 111.26 kpa