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Galina-37 [17]
3 years ago
8

If you need to write a function that will compute the cost of some candy, where each piece costs 25 cents, which would be an app

ropriate function declaration?
(A) int calculateCost(char name);
(B) char calculateCost(int count);
(C) int calculateCost int count;
(D) int calculateCost(int count);
Engineering
1 answer:
masya89 [10]3 years ago
6 0
The best answer would be

D. Int calculateCost(int count);
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Calculate the scale and speed of the pattern in order to gain useful results for a turbine operate at 150 rev/min at height diff
Rzqust [24]

Answer:

first mark me as a brainleast

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3 years ago
As a general rule of thumb, in-line engines are easier to work on than the other cylinder arrangements.
siniylev [52]

Answer:

The general rule of thumb is that the SMALLER a substance's atoms and the STRONGER the bonds, the harder the substance. Two of the strongest forms of chemical bonds are the ionic and covalent bonds.

Explanation:

5 0
3 years ago
Calculate the "exact" alkalinity of the water in Problem 3-2 if the pH is 9.43.
marin [14]

Answer:

A) approximate alkalinity = 123.361 mg/l

B) exact alkalinity = 124.708 mg/l

Explanation:

Given data :

A) determine approximate alkalinity first

Bicarbonate ion = 120 mg/l

carbonate ion = 15 mg/l

Approximate alkalinity = ( carbonate ion ) * 50/30  + ( bicarbonate ion ) * 50/61

                                   = 15 * (50/30) + 120*( 50/61 )  = 123.361 mg/l  as CaCO3

B) calculate the exact alkalinity of the water if the pH = 9.43

pH + pOH = 14

9.43 + pOH = 14. therefore pOH = 14 - 9.43 = 4.57

[OH^- ] = 10^-4.57  = 2.692*10^-5  moles/l

[ OH^- ]   = 2.692*10^-5  * 179/mole * 10^3 mg/g  = 0.458 mg/l

[ H^+ ] = 10^-9.43 * 1 * 10^3  = 3.7154 * 10^-7 mg/l

therefore the exact alkalinity can be calculated as

= ( approximate alkalinity ) + ( [ OH^- ] * 50/17 ) - ( [ H^+ ] * 50/1 )

= 123.361 + ( 0.458 * 50/17 ) - ( 3.7154 * 10^-7 * 50/1 )

= 124.708 mg/l

8 0
3 years ago
The moons light-colored highlights are
gulaghasi [49]
The light colored material in areas of the mood is the earliest crust on the moon.
3 0
3 years ago
To be safe, the engineers making the ride want to be sure the normal force does not exceed 1.8 times each persons weight - and t
Yuri [45]

Answer:

μ = 0.55

Explanation:

Given that

Normal weight = 1.8 x weight of person

N= 1.8 mg

We know that friction force Fr

Fr= μ N

μ=Coefficient of friction

N=Normal force

To find  μ We have to equate friction and gravity force

Fr= Wt

μ N = m g

μ  x 1.8 m g = m g

μ = 0.55

So the coefficient of friction will be 0.55.

5 0
3 years ago
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