Answer:
T₂=659.25 K
Explanation:
Given that
W= 25 J
Qr = 20 J
T₁ = 20⁰ = 20 +273 = 293 K
The minimum temperature of the hot reservoir = T₂
If the engine is Carnot engine then
Qa= W+ Qr
Qa=25 + 20 J
Qa= 45 J
T₂=659.25 K
Therefore the temperature of hot reservoir will be 659.25 K
Answer:
36watts
Explanation:
Data obtained from the question include:
R (Resistor) = 4 Ohms
V (Voltage) = 12V
P (power) =?
P = IV
Recall: I = V/R
P = V^2 /R
P = (12)^2 /4
P = 144/4
P = 36watts
Therefore, power is 36watts
Answer:
Explanation:
in some reactions we see this as a change in the temperature. ... The study of energy changes (particularly heat) in chemical reactions is known as ... When a chemical reaction occurs, bonds in the reactants break, while new bonds form in the product. ... Physical changes can also be classified as exothermic or endothermic.